Exercise Physics Wiki: Difference between revisions

Latest revision as of 22:56, 24 January 2011

Example:

$\nabla \cdot {\overrightarrow {B}}=0$

$\ e^{ix}=\cos {x}+i\sin {x}$ Paul Dragulin

$G_{\mu \nu }+\Lambda g_{\mu \nu }={\frac {8\pi G}{c^{4}}}T_{\mu \nu }$ Scott Miller

$\ e^{i\pi }+1=0$ Kyle Serniak

$i\hbar {\frac {\partial }{\partial t}}\Psi ={\hat {H}}\Psi$ Hang Chen

$pi^{hbar*c}+1=Psi$ Robert Bebeau

$\Delta x\Delta p\geq {\frac {\hbar }{2}}$ Taylor Hynds

$E^{2}=p^{2}c^{2}+m^{2}c^{4}$ Jordon Adams

$V=IR$ Brett Israels

$I=I_{0}e^{\tau }$ Ben Sadler

$e=\lim _{n\to \infty }\left(1+{\frac {1}{n}}\right)^{n}$ Suhib Kiswani

@@ Line 1: / Line 1: @@
-$$ E = m c^2 $$
+'''Example:'''
+<math>\nabla \cdot\overrightarrow{B} = 0</math>
+<math>\ e^{ix}=\cos{x}+i\sin{x}</math>                    Paul Dragulin
+<math> G_{\mu\nu} + \Lambda g_{\mu\nu} = \frac{8 \pi G}{c^{4}}T_{\mu\nu} </math> Scott Miller
+<math>\ e^{i\pi}+1=0 </math>     Kyle Serniak
+<math>i\hbar\frac{\partial}{\partial t} \Psi = \hat H \Psi </math>    Hang Chen
+<math>pi^{hbar*c}+1 = Psi</math>  Robert Bebeau
+<math>\Delta x\Delta p\geq \frac{\hbar}{2} </math> Taylor Hynds
+<math>E^{2}=p^{2}c^{2}+m^{2}c^{4}</math>  Jordon Adams
+<math>V=IR</math>  Brett Israels
+<math>I=I_{0}e^\tau</math> Ben Sadler
+<math>e = \lim_{n\to\infty} \left( 1 + \frac{1}{n} \right)^n</math> Suhib Kiswani