Solution to Set 6: Difference between revisions
Line 82: | Line 82: | ||
====Determine==== | ====Determine==== | ||
# Conductivity | # Conductivity | ||
<math>\rho = R \cdot \frac {A}{\ell} \;</math> | |||
<math> = \frac{V}{I} \cdot \frac {A}{\ell} \;</math> | |||
<math> = \frac{2V}{0.04A} \cdot \frac{2 \times 10^{-11}m^2}{0.002m} \;</math> | |||
<math> = 5 \times 10^{-7} \Omega \cdot m \;</math> | |||
<math>\simga = \frac{1}{\rho} = \frac{1}{5 \times 10^{-7} \Omega \cdot m} \;</math> | |||
<math> = 2 \times 10^{6} \tfrac{S}{m} \;</math> | |||
# Carrier density | # Carrier density | ||
# Mobility | # Mobility | ||
# Fermi velocity | # Fermi velocity | ||
Revision as of 01:47, 9 April 2009
Problem 1.
Given
Aluminum(Al) is trivalent with
- atomic mass amu
- density
- room temperature
- mean free time between electron collisions s.
(a) Resistivity
Calculate the resistivity of aluminum(Al) at room temperature.
Ω·m
(b) Current
If a 2-V voltage is applied to the ends of an aluminum wire 10 m long and with a cross- sectional area of
What is the current flowing through it?
Problem 2
The resistivity of a certain material at room temperature is 0.02 Wm and the Hall coefficient is . An electric field of 1 V/m is applied across it. Deduce all the information you can think of about this material.
Given
- Temperature
- Resistivity
- Hall coefficient
- Electric field
Deduction
- Conductivity
- Current Density
- Magnetic Field
Problem 3.
(a) Hall Effect Sketch
Sketch a setup used to measure the Hall effect. Label each part.
(b) Semiconductor Crystal
A semiconductor crystal is 5 mm long, 4 mm wide, and 2 mm thick. A 40mA current flows across the length of the sample after a 2-V battery is connected to the ends. When a 0.1T magnetic field is applied perpendicular to the large surface of the specimen, a Hall voltage of 15mV develops across the width of the sample.
Given
- Length L = 5 mm
- Width W = 4 mm
- Thickness H = 2 mm
- Current I = 40 mA
- Voltage V = 2 V
- Mag Field B = 0.1 T
- Hall Volt = 15 mV
Determine
- Conductivity
Failed to parse (unknown function "\simga"): {\displaystyle \simga = \frac{1}{\rho} = \frac{1}{5 \times 10^{-7} \Omega \cdot m} \;}
- Carrier density
- Mobility
- Fermi velocity
Problem 4
(a) Fermi Derivations
Derive the expressions for the Fermi energy, Fermi velocity, and electronic density of states for a two-dimensional free electron gas.
(b) Fermi Energy & Velocity of 2D Gas
A 2D electron gas formed in a GaAs/AlGaAs quantum well has a density of . Assuming that the electrons there have the free electron mass, calculate the Fermi energy and Fermi velocity.