Normalization constant: Difference between revisions
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<math>|N \rangle=|n \rangle+ \sum_{k=1}^{+\infty}\lambda ^k \left (\sum_{m_{1}}'...\sum_{m_{k}}' |m_{1} \rangle \frac {1}{E_{n}- \epsilon _{m_{1}}}\langle m_{1}|H'|m_{2} \rangle.\frac {1}{E_{n}- \epsilon _{m_{2}}}\langle m_{2}|H'|m_{3} \rangle...\frac {1}{E_{n}- \epsilon _{m_{k-1}}}\langle m_{k-1}|H'|m_{k} \rangle.\frac {1}{E_{n}- \epsilon _{m_{k}}}\langle m_{k}|H'|n \rangle \right )</math> | <math>|N \rangle=|n \rangle+ \sum_{k=1}^{+\infty}\lambda ^k \left (\sum_{m_{1}}'...\sum_{m_{k}}' |m_{1} \rangle \frac {1}{E_{n}- \epsilon _{m_{1}}}\langle m_{1}|H'|m_{2} \rangle.\frac {1}{E_{n}- \epsilon _{m_{2}}}\langle m_{2}|H'|m_{3} \rangle...\frac {1}{E_{n}- \epsilon _{m_{k-1}}}\langle m_{k-1}|H'|m_{k} \rangle.\frac {1}{E_{n}- \epsilon _{m_{k}}}\langle m_{k}|H'|n \rangle \right )</math> | ||
<math>E_{n}=\epsilon _{n}+ \lambda \langle n|H'|n \rangle + \sum_{k=1}^{+\infty}\lambda ^{k+1} \left ( \sum_{m_{1}}'...\sum_{m_{k}}' \langle n|H'|m_ {1} \rangle \frac {1}{E_{n}- \epsilon _{m_{1}}}\langle m_{1}|H'|m_{2} \rangle.\frac {1}{E_{n}- \epsilon _{m_{2}}}\langle m_{2}|H'|m_{3} \rangle...\frac {1}{E_{n}- \epsilon _{m_{k-1}}}\langle m_{k-1}|H'|m_{k} \rangle.\frac {1}{E_{n}- \epsilon _{m_{k}}}\langle m_{k}|H'|n \rangle \right ) </math> | <math>E_{n}=\epsilon _{n}+ \lambda \langle n|H'|n \rangle + </math> | ||
<math> + \sum_{k=1}^{+\infty}\lambda ^{k+1} \left ( \sum_{m_{1}}'...\sum_{m_{k}}' \langle n|H'|m_ {1} \rangle \frac {1}{E_{n}- \epsilon _{m_{1}}}\langle m_{1}|H'|m_{2} \rangle.\frac {1}{E_{n}- \epsilon _{m_{2}}}\langle m_{2}|H'|m_{3} \rangle...\frac {1}{E_{n}- \epsilon _{m_{k-1}}}\langle m_{k-1}|H'|m_{k} \rangle.\frac {1}{E_{n}- \epsilon _{m_{k}}}\langle m_{k}|H'|n \rangle \right ) </math> |
Revision as of 17:19, 17 April 2009
Using Brillouin-Wigner perturbation theory we will proof that
In this theory, the exact state and exact energy can be written as follows: