Phy5645/Energy conservation: Difference between revisions
Jump to navigation
Jump to search
Line 7: | Line 7: | ||
so the average energy in state <math> \psi </math> is: | so the average energy in state <math> \psi </math> is: | ||
<math><E>=\iiint \psi^*H\psi d^3x=\iiint \psi^*\left(-\frac{\hbar^2}{2m}\nabla^2\psi + V\psi\right) d^3x </math>, | <math><E>=\iiint \psi^*H\psi d^3x=\iiint \psi^*\left(-\frac{\hbar^2}{2m}\nabla^2\psi + V\psi\right) d^3x </math>, | ||
Using: <math>\psi^*\nabla^2\psi=\nabla\left(\psi^*\nabla\psi\right)-\nabla\psi^*\nabla\psi </math>, hence | Using: <math>\psi^*\nabla^2\psi=\nabla\left(\psi^*\nabla\psi\right)-\nabla\psi^*\nabla\psi </math>, | ||
hence: | |||
<math><E>=\iiint\left(-\frac{\hbar^2}{2m}\right)\left{\nabla\left(\psi^*\psi\right)-\nabla\psi^*\nabla\psi\right} d^3x+\iiint\psi^*\nabla\psi d^3x </math>, | <math><E>=\iiint\left(-\frac{\hbar^2}{2m}\right)\left{\nabla\left(\psi^*\psi\right)-\nabla\psi^*\nabla\psi\right} d^3x+\iiint\psi^*\nabla\psi d^3x </math>, |
Revision as of 16:31, 9 December 2009
Example 1
Consider a particle moving in a potential field , (1) Prove the average energy equation: , where W is energy density, (2) Prove the energy conservation equation: , where is energy flux density:
Prove: the energy operator in three dimensions is: so the average energy in state is: , Using: , hence: Failed to parse (syntax error): {\displaystyle <E>=\iiint\left(-\frac{\hbar^2}{2m}\right)\left{\nabla\left(\psi^*\psi\right)-\nabla\psi^*\nabla\psi\right} d^3x+\iiint\psi^*\nabla\psi d^3x } ,