Electron on Helium Surface: Difference between revisions

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</math>
</math>


This has the same form as the same form as the hydrogin atom with l=0 (s-wave). Since similar equations have similar answers, the solution to the z-component is:
This has the same form as the hydrogin atom with l=0 (s-wave). Since similar equations have similar solutions, the solution to the z-component is:


<math> Z(z) = zR_{n0}(z) </math>
<math> Z(z) = zR_{n0}(z) </math>
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<math> a_0 = \frac{hbar^2}{mQ^2e^2} </math>
<math> a_0 = \frac{hbar^2}{mQ^2e^2} </math>
(b) Turn on electric field at t=0.
The electric field introduces a perturbation to the hamiltonian:
<math> H^'(t>0) = E_0ze^{t/\tau} </math>

Revision as of 13:56, 20 April 2010

An electron close to the surface of liquid helium experiences an attractive force due to the electrostatic polarization of the helium and a repulsive force due to the exclusion principle(hard core). To a reasonable approximation for the potential when helium fills the space where Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle z<0 } :

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle V(z) = \begin{cases} -\frac{Q^2e^2}{z} &\mbox{if} \qquad z>0\\ \infty &\mbox{if} \qquad else \end{cases} }

Note: the potential is infinite when Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle z<=0} because the cannot penetrate the helium surface.


(a) Solve the Schrödinger equation. Find the Eingenenergies and Eigenvalues.

(b) An electric field is turned on at t=0 which produces the perturbation:

If the electron is initially in its ground state, find the probability makes a transition to its first excited state for times .

Solution...

(a) Solve the Schrödinger equation.

The Schrödinger equation for when is:

Using separation of variables:

For X and Y we get place waves.

This corresponds to motion parallel to the helium surface.

For z-component the Schroedinger equation becomes:

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left[ \frac{\hbar^2}{2m}\frac{\partial ^2}{\partial z^2} - \frac{Q^2e^2}{z} \right] Z(z) = }

This has the same form as the hydrogin atom with l=0 (s-wave). Since similar equations have similar solutions, the solution to the z-component is:

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Z(z) = zR_{n0}(z) }

where

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle R_{10} = \left( \frac{1}{a_0} \right) ^{3/2} z e^{ -\frac{z}{a_0} } }

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle R_{20} = \left( \frac{1}{2a_0} \right) ^{3/2} \left( 2-\frac{z}{a_0} \right) e^{ -\frac{z}{2a_0} } }


The total wave function and energies are:

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \psi = Ae^{i(k_x x + k_y y)}zR_{n0}(z) }

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E_{k_xK_yK_z} = \frac{\hbar^2}{2m} \left( k_x^2 + k_y^2 \right) -\frac{Q^4e^4m}{2\hbar^2n^2} }

where n = 1,2,... is the quantum number for the z-direction and the bohr radius has become

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a_0 = \frac{hbar^2}{mQ^2e^2} }


(b) Turn on electric field at t=0.

The electric field introduces a perturbation to the hamiltonian:

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle H^'(t>0) = E_0ze^{t/\tau} }