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(New page: For a spin 1 system l = 1 and m = -1 , 0 , 1. For the operator <math>S_{z}</math> we have <math>S_z |l,m \rangle</math> \Rightarrow <math>\left \langle l,n| S_z|l,m \rangle = m\hbar \l...) |
(No difference)
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Revision as of 23:04, 30 April 2010
For a spin 1 system l = 1 and m = -1 , 0 , 1. For the operator we have
\Rightarrow Failed to parse (syntax error): {\displaystyle \left \langle l,n| S_z|l,m \rangle = m\hbar \langle l,n|l,m \rangle}
So
\Rightarrow