Exercise PhysicsWiki: Difference between revisions
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<math>e^{i\pi} + 1 = 0</math> (Steve Honeywell) | <math>e^{i\pi} + 1 = 0</math> (Steve Honeywell) | ||
:<math> \psi (x, \ t) = A e^{i \left( kx - \omega t \right)} \ , </math> (Michael Brandow) | |||
<math>f=\langle P, Q, R \rangle</math> | |||
<math>\nabla f = \langle {\partial f \over \partial P} + {\partial f \over \partial Q} + {\partial f \over \partial R} \rangle</math> (Andrew Wray) | |||
<math>U=0.5kx^2</math> (Ryan Taylor) | |||
<math>\nabla^2\psi = \frac{1}{v^2}\frac{\partial^2\psi}{\partial t^2} </math> (Matthew Denagy) | |||
<math>F = G{m1m2 \over r^2 } </math> (August Larson) | |||
<math>\frac{-\hbar^2}{2m}\nabla^2\psi(r) + V(r)\psi(r) = E\psi(r)</math> (Brandon Bryant) | |||
<math>E = mc^2</math> Cheyvonne Perry | |||
<math>F = ma</math> (Jamie Kalb) |
Latest revision as of 16:12, 31 August 2009
$$a=b$$
(posted by TerriC, Group 2)
(Zach McDargh)
(posted by KimberlyWynne 19:05, 29 August 2009 (EDT))
(Sandy Simmons)
(Steve Honeywell)
- (Michael Brandow)
(Andrew Wray)
(Ryan Taylor)
(Matthew Denagy)
(August Larson)
(Brandon Bryant)
Cheyvonne Perry
(Jamie Kalb)