Delta Potential Born Approximation: Difference between revisions

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Problem
In the Born approximation, the scattering amplitude is


Calculate the Born approximation to the differential and total cross sections for a particle of mass ''m'' off the <math>\delta</math>-function potential <math>V(\mathbf{r})=g\delta^3(\mathbf{r})</math>.
<math>f_{\text{Born}}(\theta)=-\frac{m}{2\pi\hbar^2}\int d^3\mathbf{r'}\,V(\mathbf{r'})e^{-i\mathbf{q}\cdot\mathbf{r}'},</math>


Solution:
where <math>\mathbf{q}=\mathbf{k}'-\mathbf{k}</math> and <math>\mathbf{k}</math> and <math>\mathbf{k}'</math> are the wave vectors of the incident and scattered waves, respectively.  Substituting in the delta function potential, we get


In Born approximation,  
<math>f_B(\theta)=-\frac{m}{2\pi\hbar^2}\int d^3\mathbf{r'}\,g\delta^3(\mathbf{r}')e^{-i\mathbf{q}\cdot\mathbf{r}'}=-\frac{mg}{2\pi\hbar^2},</math>


<math>f_B(\theta)=-\frac{m}{2\pi\hbar^2}\int V(r')e^{-i\mathbf{q}\cdot\mathbf{r}'}d^3r'</math>
and therefore the differential cross section is


where <math>\mathbf{q}=\mathbf{k}'-\mathbf{k}</math> with <math>\mathbf{k}</math> and <math>\mathbf{k}'</math> are the wave vectors of the incident and scattered waves, respectively. Then
<math>\frac{d\sigma}{d\Omega}=|f_{\text{Born}}(\theta)|^2=\frac{m^2 g^2}{4\pi^2\hbar^4}.</math>


<math>f_B(\theta)=-\frac{m}{2\pi\hbar^2}g\int e^{-i\mathbf{q}\cdot\mathbf{r}'}d^3r'</math>
As the distribution is isotropic, the total cross section is


<math>\sigma=4\pi\sigma=\frac{m^2 g^2}{\pi\hbar^4}</math>.


i\hbar\frac{\partial \psi(\textbf{r},t)}{\partial t} = \left[ -\frac{\hbar^2}{2m}\nabla^2 + V(\textbf{r})\right]\psi(\textbf{r},t
Back to [[Differential Cross Section and the Green's Function Formulation of Scattering#Problems|Differential Cross Section and the Green's Function Formulation of Scattering]]

Latest revision as of 13:48, 18 January 2014

In the Born approximation, the scattering amplitude is

where and and are the wave vectors of the incident and scattered waves, respectively. Substituting in the delta function potential, we get

and therefore the differential cross section is

As the distribution is isotropic, the total cross section is

.

Back to Differential Cross Section and the Green's Function Formulation of Scattering