Phy5645/AngularMomentumProblem: Difference between revisions

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Posted by Group 6:
We first rewrite the wave vector in Dirac notation:
A system is initally in the state: 
 
:<math>psi(theta,phi)=1/sqrt{5}<math>
<math>|\psi\rangle=\frac{1}{\sqrt{5}}|1,-1\rangle+\sqrt{\frac{3}{5}}|1,0\rangle+1/\sqrt{5}|1,1\rangle</math>
 
We see that the possible results for a measurement of <math>\hat{L}_z</math> are <math>-\hbar,</math> <math>0,\!</math> and <math>\hbar.</math>
 
The probablity for obtaining <math>-\hbar</math> is
 
<math>P(-\hbar)=|\langle 1,-1|\psi\rangle|^2=\left |\frac{1}{\sqrt{5}}\langle 1,-1|1,-1\rangle+\sqrt{\frac{3}{5}}\langle 1-1|1,0\rangle+\frac{1}{\sqrt{5}}\langle 1,-1|1,1\rangle\right |^2=\tfrac{1}{5}.</math>
 
Similarly, the probablites of obtaining <math>0\!</math> and <math>\hbar</math> are
 
<math>P(0)=|\langle 1,0|\psi\rangle|^2=\tfrac{3}{5}</math>
 
and
 
<math>P(\hbar)=|\langle 1,1|\psi\rangle|^2=\tfrac{1}{5}.</math>
 
Back to [[Orbital Angular Momentum Eigenfunctions#Problem|Orbital Angular Momentum Eigenfunctions]]

Latest revision as of 13:40, 18 January 2014

We first rewrite the wave vector in Dirac notation:

We see that the possible results for a measurement of are and

The probablity for obtaining is

Similarly, the probablites of obtaining and are

and

Back to Orbital Angular Momentum Eigenfunctions