Phy5645/Hydrogen Atom WKB: Difference between revisions

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<math>T=-\frac{\hbar^{2}(l+\tfrac{1}{2})}{2mE}</math> and <math>V=\frac{e^{2}}{E},</math>
<math>T=-\frac{\hbar^{2}(l+\tfrac{1}{2})}{2mE}</math> and <math>V=\frac{e^{2}}{E},</math>


<math>\sqrt {2mE} \int\limits_{r1}^{r2} {(1+\frac{T}{r^{2}}}+\frac{V}{r})^{1/2}dr=(n+\frac{1}{2})\pi \hbar \text{ }</math>
<math>\sqrt{2mE}\int_{r_1}^{r_2}\sqrt{1-\frac{V}{r}+\frac{T}{r^{2}}}\,dr=(n+\tfrac{1}{2})\pi \hbar.</math>


<math>\text{the relation  r}^{2}-Vr+T=(r_{1}-r)(r_{2}-r)</math>
Using the fact that <math>r^{2}-Vr+T=(r_{1}-r)(r_{2}-r)\!</math> and


<math>\sqrt {2mE} \int\limits_{r1}^{r2} {\left ({\frac{(r_{1}-r)(r_{2}-r)}{r^{2}}} \right )^{1/2}dr=(n+\frac{1}{2})\pi \hbar }</math>
<math>\sqrt {2mE} \int\limits_{r1}^{r2} {\left ({\frac{(r_{1}-r)(r_{2}-r)}{r^{2}}} \right )^{1/2}dr=(n+\frac{1}{2})\pi \hbar }</math>

Revision as of 02:45, 13 January 2014

The WKB approximation is given by

where

We may rewrite the above as

or, making the substitution,

and

Using the fact that and

Then if we finally pull out E,

Back to WKB in Spherical Coordinates