Solution to Set 1

Problem 1

(a)

It is a common misconception that Max Planck derived his now-famous law, Planck's Law, in order to resolve the so-called "ultraviolet catastrophe," which predicts, from classical physics, that a blackbody will emit greater and greater intensity radiation at shorter wavelengths, thus outputting infinite power as electromagnetic radiation. In fact, this problem was not noticed until five years after Planck derived his law.

What actually motivated Planck was his desire to improve on the Wien approximation, which fit known blackbody radiation spectra only at short wavelengths. Expressed as spectral radiance:

$I(\lambda ,T)={\frac {2hc^{2}}{\lambda ^{5}}}e^{-{\frac {hc}{\lambda kT}}}$

Conversely, the Rayleigh-Jeans law fit the data only at long wavelengths:

$I(\lambda ,T)={\frac {2ckT}{\lambda ^{4}}}$

Planck derived his function to fit the data at all wavelengths:

$I(\lambda ,T)={\frac {2hc^{2}}{\lambda ^{5}}}{\frac {1}{e^{\frac {hc}{\lambda kT}}-1}}$

Planck derived his law via a consideration of various ways in which electromagnetic energy can be distributed over the different modes of oscillation of charged oscillators in matter (today known to be atoms). He found that when he assumed the energy to be quantized, the above law emerged and fit the data very well.

(b)

Planck's law, expressed as spectral radiance in terms of wavelength and temperature:

$I(\lambda ,T)={\frac {2hc^{2}}{\lambda ^{5}}}{\frac {1}{e^{\frac {hc}{\lambda kT}}-1}}$

Wien's displacement law:

$\lambda _{\mathrm {max} }={\frac {b}{T}}$

Where $\lambda _{\mathrm {max} }$ is the wavelength of maximum intensity electromagnetic radiation output for a blackbody in thermal equilibrium at absolute temperature $T$, and $b$ is a proportionality constant (for our purposes here, it will not be necessary to calculate the value of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b} , only to show that it must be a constant).

Differentiating Planck's law with respect to Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lambda} :

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{dI}{d\lambda} = 2hc^2\left(-\frac{5}{\lambda^6}\frac{1}{e^{\frac{hc}{\lambda kT}}-1} + \frac{1}{\lambda^5}\frac{hc}{kT}\frac{1}{\lambda^2}\frac{e^{\frac{hc}{\lambda kT}}}{(e^{\frac{hc}{\lambda kT}}-1)^2}\right) = 2hc^2\left(-\frac{5}{\lambda^6}\frac{1}{e^{\frac{hc}{\lambda kT}}-1} + \frac{hc}{\lambda^7 kT}\frac{e^{\frac{hc}{\lambda kT}}}{(e^{\frac{hc}{\lambda kT}}-1)^2}\right)}

To find Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lambda_{\mathrm{max}}} , we set Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{dI}{d\lambda} = 0} and solve:

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2hc^2\left(-\frac{5}{\lambda_{\mathrm{max}}^6}\frac{1}{e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}-1} + \frac{hc}{\lambda_{\mathrm{max}}^7 kT}\frac{e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}}{(e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}-1)^2}\right) = 0}

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -\frac{5}{\lambda_{\mathrm{max}}^6}\frac{1}{e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}-1} + \frac{hc}{\lambda_{\mathrm{max}}^7 kT}\frac{e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}}{(e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}-1)^2} = 0}

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{hc}{\lambda_{\mathrm{max}}^7 kT}\frac{e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}}{(e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}-1)^2} = \frac{5}{\lambda_{\mathrm{max}}^6}\frac{1}{e^{\frac{hc}{\lambda_{\mathrm{max}} kT}}-1}}

${\frac {hc}{\lambda _{\mathrm {max} }kT}}{\frac {e^{\frac {hc}{\lambda _{\mathrm {max} }kT}}}{e^{\frac {hc}{\lambda _{\mathrm {max} }kT}}-1}}=5$

${\frac {hc}{\lambda _{\mathrm {max} }kT}}{\frac {1}{1-e^{-{\frac {hc}{\lambda _{\mathrm {max} }kT}}}}}=5$

Now, for simplicity we define:

$\chi \equiv {\frac {hc}{\lambda _{\mathrm {max} }kT}}$

and we have:

${\frac {\chi }{1-e^{-\chi }}}=5$

It is clear from the above equation that $\chi$ must be a constant. If $\chi$ is a constant, then examination of its definition above reveals only two non-constant terms: $\lambda$ and $T$. We thus rearrange the $\chi$ equation to give a simple relation between these two variables:

$\lambda _{\mathrm {max} }={\frac {hc}{k\chi }}{\frac {1}{T}}$

Defining a constant of proportionality $b$:

$b\equiv {\frac {hc}{k\chi }}$

We now have Wien's displacement law in its most general form:

$\lambda _{\mathrm {max} }={\frac {b}{T}}$