Solution to Set 6: Difference between revisions

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If a 2-V voltage is applied to the ends of an aluminum wire 10 m long and with a cross- sectional area of <math>1 mm^2</math>  
If a 2-V voltage is applied to the ends of an aluminum wire 10 m long and with a cross- sectional area of <math>1 mm^2</math>  


<math>R = \frac{\iota \cdot \rho}{A} \;</math>
<math>R = \frac{\ell \cdot \rho}{A} \;</math>
<math> = \frac{\left (10m  \right ) \cdot \left (2.646 \times 10^{-8} \Omega \cdot m  \right )}{\left (10^{-6}m  \right )} \;</math>
<math> = \frac{\left (10m  \right ) \cdot \left (2.646 \times 10^{-8} \Omega \cdot m  \right )}{\left (10^{-6}m  \right )} \;</math>
<math> = 0.2646 \Omega \;</math>
<math> = 0.2646 \Omega \;</math>

Revision as of 01:57, 9 April 2009

Problem 1.

Given

Aluminum(Al) is trivalent with

  • atomic mass amu
  • density
  • room temperature
  • mean free time between electron collisions s.

(a) Resistivity

Calculate the resistivity of aluminum(Al) at room temperature.

Ω·m

(b) Current

Wire cross section.gif

If a 2-V voltage is applied to the ends of an aluminum wire 10 m long and with a cross- sectional area of

What is the current flowing through it?

Problem 2

Detective.gif

The resistivity of a certain material at room temperature is 0.02 Wm and the Hall coefficient is . An electric field of 1 V/m is applied across it. Deduce all the information you can think of about this material.

Given

  • Temperature
  • Resistivity
  • Hall coefficient
  • Electric field

Deduction

  • Conductivity

  • Current Density

  • Magnetic Field

Problem 3.

(a) Hall Effect Sketch

Sketch a setup used to measure the Hall effect. Label each part.

Hall Effect.jpg

(b) Semiconductor Crystal

A semiconductor crystal is 5 mm long, 4 mm wide, and 2 mm thick. A 40mA current flows across the length of the sample after a 2-V battery is connected to the ends. When a 0.1T magnetic field is applied perpendicular to the large surface of the specimen, a Hall voltage of 15mV develops across the width of the sample.

Given

  • Length L = 5 mm
  • Width W = 4 mm
  • Thickness H = 2 mm
  • Current I = 40 mA
  • Voltage V = 2 V
  • Mag Field B = 0.1 T
  • Hall Volt = 15 mV

Determine

  1. Conductivity

  1. Carrier density

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle R_H = \frac{E_y}{\mathbf{J_x} \cdot B} \;} Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = -\frac{1}{ne} \;}

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = - \frac{1}{-1.602 \times 10^{-19}C} \cdot \frac{0.015V}{\left (0.04A \right ) \cdot \tfrac{\left (0.1T \right )}{\left (0.002m \right )}} \;}

  1. Mobility
  1. Fermi velocity

Problem 4

(a) Fermi Derivations

Derive the expressions for the Fermi energy, Fermi velocity, and electronic density of states for a two-dimensional free electron gas.

(b) Fermi Energy & Velocity of 2D Gas

A 2D electron gas formed in a GaAs/AlGaAs quantum well has a density of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2{\rm x}10^{11} cm^{-2}} . Assuming that the electrons there have the free electron mass, calculate the Fermi energy and Fermi velocity.