Solution to Set 6: Difference between revisions
m (→(b) Current) |
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If a 2-V voltage is applied to the ends of an aluminum wire 10 m long and with a cross- sectional area of <math>1 mm^2</math> | If a 2-V voltage is applied to the ends of an aluminum wire 10 m long and with a cross- sectional area of <math>1 mm^2</math> | ||
<math>R = \frac{\ | <math>R = \frac{\ell \cdot \rho}{A} \;</math> | ||
<math> = \frac{\left (10m \right ) \cdot \left (2.646 \times 10^{-8} \Omega \cdot m \right )}{\left (10^{-6}m \right )} \;</math> | <math> = \frac{\left (10m \right ) \cdot \left (2.646 \times 10^{-8} \Omega \cdot m \right )}{\left (10^{-6}m \right )} \;</math> | ||
<math> = 0.2646 \Omega \;</math> | <math> = 0.2646 \Omega \;</math> |
Revision as of 01:57, 9 April 2009
Problem 1.
Given
Aluminum(Al) is trivalent with
- atomic mass amu
- density
- room temperature
- mean free time between electron collisions s.
(a) Resistivity
Calculate the resistivity of aluminum(Al) at room temperature.
Ω·m
(b) Current
If a 2-V voltage is applied to the ends of an aluminum wire 10 m long and with a cross- sectional area of
What is the current flowing through it?
Problem 2
The resistivity of a certain material at room temperature is 0.02 Wm and the Hall coefficient is . An electric field of 1 V/m is applied across it. Deduce all the information you can think of about this material.
Given
- Temperature
- Resistivity
- Hall coefficient
- Electric field
Deduction
- Conductivity
- Current Density
- Magnetic Field
Problem 3.
(a) Hall Effect Sketch
Sketch a setup used to measure the Hall effect. Label each part.
(b) Semiconductor Crystal
A semiconductor crystal is 5 mm long, 4 mm wide, and 2 mm thick. A 40mA current flows across the length of the sample after a 2-V battery is connected to the ends. When a 0.1T magnetic field is applied perpendicular to the large surface of the specimen, a Hall voltage of 15mV develops across the width of the sample.
Given
- Length L = 5 mm
- Width W = 4 mm
- Thickness H = 2 mm
- Current I = 40 mA
- Voltage V = 2 V
- Mag Field B = 0.1 T
- Hall Volt = 15 mV
Determine
- Conductivity
- Carrier density
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle R_H = \frac{E_y}{\mathbf{J_x} \cdot B} \;} Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = -\frac{1}{ne} \;}
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = - \frac{1}{-1.602 \times 10^{-19}C} \cdot \frac{0.015V}{\left (0.04A \right ) \cdot \tfrac{\left (0.1T \right )}{\left (0.002m \right )}} \;}
- Mobility
- Fermi velocity
Problem 4
(a) Fermi Derivations
Derive the expressions for the Fermi energy, Fermi velocity, and electronic density of states for a two-dimensional free electron gas.
(b) Fermi Energy & Velocity of 2D Gas
A 2D electron gas formed in a GaAs/AlGaAs quantum well has a density of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2{\rm x}10^{11} cm^{-2}} . Assuming that the electrons there have the free electron mass, calculate the Fermi energy and Fermi velocity.