Exercise PhysicsWiki: Difference between revisions

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(Kepler's 1st Law)
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<math>r=\frac{p}{1+\varepsilon\cdot\cos\theta}</math>  
<math>r=\frac{p}{1+\varepsilon\cdot\cos\theta}</math>  
(posted by [[User:KimberlyWynne|KimberlyWynne]] 19:05, 29 August 2009 (EDT))
(posted by [[User:KimberlyWynne|KimberlyWynne]] 19:05, 29 August 2009 (EDT))
<math> x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} </math> (Sandy Simmons)

Revision as of 22:47, 29 August 2009

$$a=b$$

(posted by TerriC, Group 2)

(Zach McDargh)

(posted by KimberlyWynne 19:05, 29 August 2009 (EDT))

(Sandy Simmons)