Exercise PhysicsWiki: Difference between revisions
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(Kepler's 1st Law) |
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<math>r=\frac{p}{1+\varepsilon\cdot\cos\theta}</math> | <math>r=\frac{p}{1+\varepsilon\cdot\cos\theta}</math> | ||
(posted by [[User:KimberlyWynne|KimberlyWynne]] 19:05, 29 August 2009 (EDT)) | (posted by [[User:KimberlyWynne|KimberlyWynne]] 19:05, 29 August 2009 (EDT)) | ||
<math> x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} </math> (Sandy Simmons) |
Revision as of 22:47, 29 August 2009
$$a=b$$
(posted by TerriC, Group 2)
(Zach McDargh)
(posted by KimberlyWynne 19:05, 29 August 2009 (EDT))
(Sandy Simmons)