Exercise PhysicsWiki: Difference between revisions
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<math>e^{i\pi} + 1 = 0</math> (Steve Honeywell) | <math>e^{i\pi} + 1 = 0</math> (Steve Honeywell) | ||
<math>f=\langle P, Q, R \rangle</math> | |||
<math>\nabla f = {\partial f \over \partial x} P + {\partial f \over \partial y} Q + {\partial f \over \partial z} R</math> (Andrew Wray) |
Revision as of 03:05, 30 August 2009
$$a=b$$
(posted by TerriC, Group 2)
(Zach McDargh)
(posted by KimberlyWynne 19:05, 29 August 2009 (EDT))
(Sandy Simmons)
(Steve Honeywell)
(Andrew Wray)