Exercise PhysicsWiki: Difference between revisions

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<math>U=0.5kx^2</math> (Ryan Taylor)
<math>U=0.5kx^2</math> (Ryan Taylor)


<math>\nabla^2\psi = \frac{1}{v^2}\frac{\partial^2\psi}{\partial t^2}
<math>\nabla^2\psi = \frac{1}{v^2}\frac{\partial^2\psi}{\partial t^2} </math>
 
 
 
<math>F = G{m1m2 \over r^2 } </math> (August Larson)

Revision as of 16:51, 30 August 2009

$$a=b$$

(posted by TerriC, Group 2)

(Zach McDargh)

(posted by KimberlyWynne 19:05, 29 August 2009 (EDT))

(Sandy Simmons)

(Steve Honeywell)



(Andrew Wray)


(Ryan Taylor)


(August Larson)