Exercise PhysicsWiki: Difference between revisions

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<math>F = G{m1m2 \over r^2 } </math> (August Larson)
<math>F = G{m1m2 \over r^2 } </math> (August Larson)
<math>\frac{-\hbar^2}{2m}\nabla^2\psi(r) + V(r)\psi(r) = E\psi(r)</math> (Brandon Bryant)

Revision as of 00:27, 31 August 2009

$$a=b$$

(posted by TerriC, Group 2)

(Zach McDargh)

(posted by KimberlyWynne 19:05, 29 August 2009 (EDT))

(Sandy Simmons)

(Steve Honeywell)



(Andrew Wray)


(Ryan Taylor)


(August Larson)


(Brandon Bryant)