Phy5645/angularmomcommutation/: Difference between revisions

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'''Question:''' In the angular momentum basis, compute <math>\left \langle {l,m\left |{L_{x}^{2}} \right |l,m} \right \rangle </math>  and <math>\left \langle {l,m\left |{L_{x}L_{y}} \right |l,m} \right \rangle </math>.
'''(a)''' <math>\left \langle {l,m\left |{L_{x}^{2}} \right |l,m} \right \rangle </math>
 
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'''Solution:'''
 
* <math>\left \langle {l,m\left |{L_{x}^{2}} \right |l,m} \right \rangle </math>


Since <math>L_{x}=\frac{L_{+}+L_{-}}{2}</math>, we can obtain <math>L_{x}^{2}</math>;
Since <math>L_{x}=\frac{L_{+}+L_{-}}{2}</math>, we can obtain <math>L_{x}^{2}</math>;
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* <math>\left \langle {l,m\left |{L_{x}L_{y}} \right |l,m} \right \rangle </math>
'''(b)''' <math>\left \langle {l,m\left |{L_{x}L_{y}} \right |l,m} \right \rangle </math>


<math>L_{x}L_{y}=\frac{L_{+}+L_{-}}{2}\frac{L_{+}-L_{-}}{2i}</math>
<math>L_{x}L_{y}=\frac{L_{+}+L_{-}}{2}\frac{L_{+}-L_{-}}{2i}</math>
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<math>=\frac{\hbar ^{2}}{4i}(-2m)=\frac{i\hbar ^{2}m}{2}</math>
<math>=\frac{\hbar ^{2}}{4i}(-2m)=\frac{i\hbar ^{2}m}{2}</math>


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Revision as of 21:50, 29 August 2013

(a)

Since , we can obtain ;

By definition, and won't contribute because and


(b)

Again, and won't contribute

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