Phy5645/Energy conservation

Example 1

Consider a particle moving in a potential field $V({\textbf {r}})$, (1) Prove the average energy equation: $<E>=\int Wd^{3}x=\int \left[{\frac {\hbar ^{2}}{2m}}\nabla \psi ^{*}\cdot \nabla \psi \right]d^{3}x$, where W is energy density, (2) Prove the energy conservation equation: ${\frac {\partial W}{\partial t}}+\nabla \cdot {\textbf {S}}=0$, where ${\textbf {S}}$ is energy flux density: ${\textbf {S}}=-{\frac {\hbar ^{2}}{2m}}\left({\frac {\partial \psi ^{*}}{\partial t}}\nabla \psi +{\frac {\partial \psi }{\partial t}}\nabla \psi ^{*}\right)$

Prove: the energy operator in three dimensions is: $H=-{\frac {\hbar ^{2}}{2m}}\nabla ^{2}+V$ so the average energy in state $\psi$ is: $<E>=\iiint \psi ^{*}H\psi d^{3}x=\iiint \psi ^{*}\left(-{\frac {\hbar ^{2}}{2m}}\nabla ^{2}\psi +V\psi \right)d^{3}x$, Using: $\psi ^{*}\nabla ^{2}\psi =\nabla \left(\psi ^{*}\nabla \psi \right)-\nabla \psi ^{*}\nabla \psi$, hence: $<E>=\iiint \left(-{\frac {\hbar ^{2}}{2m}}\right)\left(\nabla \left(\psi ^{*}\nabla \psi \right)-\nabla \psi ^{*}\nabla \psi \right)d^{3}x+\iiint \psi ^{*}\nabla \psi d^{3}x=-{\frac {\hbar ^{2}}{2m}}\iiint \nabla \left(\psi ^{*}\nabla \psi \right)d^{3}x+{\frac {\hbar ^{2}}{2m}}\iiint \nabla \psi ^{*}\nabla \psi d^{3}x+\iiint \psi ^{*}\nabla \psi d^{3}x$,

Using Gauss Theorem for the last term: $-{\frac {\hbar ^{2}}{2m}}\iiint \nabla \left(\psi ^{*}\nabla \psi \right)d^{3}x=\iint \psi ^{*}\nabla \psi \cdot d{\textbf {S}}$,