Phy5645/Energy conservation: Difference between revisions

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<math>=\frac{\hbar^2}{2m}\left(\nabla\cdot\left(\nabla\psi^*\cdot\frac{\partial\psi}{\partial t} + \frac{\partial\psi^*}{\partial t}\cdot\nabla\psi\right) - \left(\frac{\partial\psi}{\partial t}\nabla^2\psi^*+\frac{\partial\psi^*}{\partial t}\nabla^2\psi\right)\right)+\frac{\partial\psi^*}{\partial t}\nabla\psi+\psi^*\nabla\frac{\partial\psi}{\partial t}</math>
<math>=\frac{\hbar^2}{2m}\left(\nabla\cdot\left(\nabla\psi^*\cdot\frac{\partial\psi}{\partial t} + \frac{\partial\psi^*}{\partial t}\cdot\nabla\psi\right) - \left(\frac{\partial\psi}{\partial t}\nabla^2\psi^*+\frac{\partial\psi^*}{\partial t}\nabla^2\psi\right)\right)+\frac{\partial\psi^*}{\partial t}\nabla\psi+\psi^*\nabla\frac{\partial\psi}{\partial t}</math>
<math>=\frac{\hbar^2}{2m}\nabla\cdot\left(\nabla\psi^*\cdot\frac{\partial\psi}{\partial t} + \frac{\partial\psi^*}{\partial t}\cdot\nabla\psi\right)+\frac{\partial\psi^*}{\partial t}\left(-\frac{\hbar^2}{2m}\nabla^2\psi+\nabla\psi\right)+\frac{\partial\psi}{\partial t}\left(-\frac{\hbar^2}{2m}\nabla^2\psi^*+\nabla\psi^*\right)</math>,
<math>=\frac{\hbar^2}{2m}\nabla\cdot\left(\nabla\psi^*\cdot\frac{\partial\psi}{\partial t} + \frac{\partial\psi^*}{\partial t}\cdot\nabla\psi\right)+\frac{\partial\psi^*}{\partial t}\left(-\frac{\hbar^2}{2m}\nabla^2\psi+\nabla\psi\right)+\frac{\partial\psi}{\partial t}\left(-\frac{\hbar^2}{2m}\nabla^2\psi^*+\nabla\psi^*\right)</math>,
Using Schrodinger Equations:
<math>i\hbar\frac{\partial\psi}{\partial t}=-\frac{\hbar^2}{2m}\nabla^2\psi+\nabla\psi</math>,
<math>-i\hbar\frac{\partial\psi^*}{\partial t}=-\frac{\hbar^2}{2m}\nabla^2\psi^*+\nabla\psi^*</math>,

Revision as of 21:20, 9 December 2009

Example 1

Consider a particle moving in a potential field , (1) Prove the average energy equation: , where W is energy density, (2) Prove the energy conservation equation: , where is energy flux density:

Prove:(1): the energy operator in three dimensions is: so the average energy in state is: , Using: , hence: ,

Using Gauss Theorem for the last term: , with the condition: , for infinite surface.

Hence:

(2):first we find the time derivative of energy density: , ,

Using Schrodinger Equations: , ,