Phy5646/AddAngularMomentumProb: Difference between revisions
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1.) First express <math>\ S^2</math> in terms of <math>\ S_1^2</math>, <math>\ S_2^2</math>, <math>\ S_{1z}</math>, <math>\ S_{2z}</math>, <math>\ S_{1\plusmn}</math> and <math>\ S_{2\plusmn}</math>: | 1.) First express <math>\ S^2</math> in terms of <math>\ S_1^2</math>, <math>\ S_2^2</math>, <math>\ S_{1z}</math>, <math>\ S_{2z}</math>, <math>\ S_{1\plusmn}</math> and <math>\ S_{2\plusmn}</math>: | ||
<math>\ S^2 = (\vec{S_1} + \vec{S_2})^2 = S_1^2 + S_2^2 +2\vec{S_1} \cdot \vec{S_2} = S_1^2 + S_2^2 + 2(S_{1x}S_{2x} + S_{1y}S_{2y} + S_{1z}S_{2z}) = S_1^2 + S_2^2 + 2S_{1z}S_{2z}+S_{1+}S_{2-}+S_{1-}S_{2+}</math> | <math>\ S^2 = (\vec{S_1} + \vec{S_2})^2 = S_1^2 + S_2^2 +2\vec{S_1} \cdot \vec{S_2} = S_1^2 + S_2^2 + 2(S_{1x}S_{2x} + S_{1y}S_{2y} + S_{1z}S_{2z}) = S_1^2 + S_2^2 + 2S_{1z}S_{2z}+S_{1+}S_{2-}+S_{1-}S_{2+}</math> | ||
2.) | 2.) Then act with this on direct product state <math>\ |m_1m_2\rangle </math>: | ||
<math>\ S^2|m_1m_2\rangle = (S_1^2 + S_2^2 + 2S_{1z}S_{2z}+S_{1+}S_{2-}+S_{1-}S_{2+})|m_1m_2\rangle </math> | |||
<math>\ = S_1^2|m_1m_2\rangle + S_2^2|m_1m_2\rangle + 2S_{1z}S_{2z}|m_1m_2\rangle+S_{1+}S_{2-}|m_1m_2\rangle+S_{1-}S_{2+}|m_1m_2\rangle </math> | |||
<math>\ = \hbar^2 \frac{1}{2}\left(\frac{1}{2}+1 \right)|m_1m_2\rangle + \hbar^2\frac{1}{2}\left(\frac{1}{2}+1\right)|m_1m_2\rangle | |||
</math> | |||
Revision as of 19:33, 25 April 2010
Based on exercise 15.1.1. from Principles of Quantum Mechanics, 2nd ed. by Shankar:
Express as a matrix for two spin-1/2 particles in the direct product basis.
1.) First express in terms of , , , , and :
2.) Then act with this on direct product state :