Phy5670/Bethe Ansatz testing: Difference between revisions
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First consider n1 and n2 are not neighboring pairs | First consider n1 and n2 are not neighboring pairs i.e.<math>\ \ n_1+1<n_2 </math>. Then by acting the Hamiltonian to the eigenstate, we get | ||
<math>(H-E_{0})|n_{1},n_{2} \rangle = 2J|n_{1},n_{2} \rangle | <math>(H-E_{0})|n_{1},n_{2} \rangle = 2J|n_{1},n_{2} \rangle |
Revision as of 17:01, 9 December 2010
Bethe-Ansatz for 1D-Heisenberg Model
The Bethe ansatz was originally developed for the one-dimensional Heisenberg model with nearest neighbor interaction and periodic boundary conditions:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle H=-J\sum^N_{n=1}\vec{S}_n\cdot \vec{S}_{n+1}=-J\sum^N_{n=1}\left[\frac{1}{2}(S_n^+S^-_{n+1} + S_n^-S^+_{n+1})+S^z_nS^z_{n+1} \right] }
where J>0 for Ferromagnet and J<0 for Anti-Ferromagnet.
In the ferromagnetic ground state, all spins are aligned in one direction along. We take it as z-direction. Thus, the ground state can be described as:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |F\rangle = |\uparrow\uparrow\uparrow...\uparrow\rangle }
and when the Hamiltonian act on it, only the last term of the Hamiltonian contribute energy and the ground state energy is:
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E_{0}=-\frac{NJ}{4} }
case of only one flipped spin
If now two of the up spins are flipped to down spins, and if these 2 spins are in position n1 and n2, we can specify the state as:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |n_1,n_2\rangle = |\uparrow\uparrow\underbrace{\downarrow}_{n_1}\uparrow..\uparrow\underbrace{\downarrow}_{n_2} \uparrow...\uparrow\rangle }
As Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle [S_{z},H]=0 } , so one may expect Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |n_1,n_2\rangle } to be a eigenstate of the Hamiltonian, but it is not as the flipping operators change the position of the spin and so change the state.
However the superpositions of states which have same number of flipped spins with the spin being put at different combination of positions give the eigenstate of the Hamiltonian.
Eigenstate is given by superpositions of states with only one flipped spin at the lattice site n:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\Psi\rangle = \sum^N_{n=1}a(n)|n\rangle }
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{align} (H-E_{0})|n\rangle &= J|n\rangle -\frac{J}{2}(|n+1\rangle|+|n-1\rangle) \\ \langle \Psi|(H-E_{0})|n\rangle &= J\langle \Psi|n\rangle -\frac{J}{2}\langle \Psi|(|n+1\rangle|+|n-1\rangle) \\ 2\left [E-E_{0}\right ]a(n) &=J\left [2a(n)-a(n-1)-a(n+1)\right ] \end{align}}
which is a difference equation. By applying periodic boundary condition Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a(n+N)=a(n)} we obtain plane wave coefficients (we call it spin wave):
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a(n)=e^{ik_{m}n}, \qquad k_{m}=\frac{2\pi}{N}m \qquad \text{where} \quad m=0,1,... N-1 }
Thus, the eigenvectors are given by superpositions of states with only one flipped spin with spin wave coefficient and the energy of these states are given by:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E=E_{0}+J\left [1-cos(k_{m})\right ] \qquad \text{where} \quad m=0,1,... N-1 }
case of 2 flipped spins
Eigenstate is superposition of all states which have same number of flipped spins:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\Psi\rangle = \sum^N_{n_{1}<n_{2}}a(n_1,n_2)|n_1,n_2\rangle }
where we have assumed Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle n_1<n_2 } .
First consider n1 and n2 are not neighboring pairs i.e.Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ \ n_1+1<n_2 } . Then by acting the Hamiltonian to the eigenstate, we get
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (H-E_{0})|n_{1},n_{2} \rangle = 2J|n_{1},n_{2} \rangle -\frac{J}{2}\left [|n_1+1,n_2\rangle +|n_1-1,n_2\rangle + |n_1,n_2+1\rangle + |n_1,n_2-1\rangle \right ] }
adding Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle \Psi } on it we get:
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{E-E_{0}}{J}a(n_1,n_2) = 2a(n_{1},n_{2}) -\frac{1}{2}\left [a(n_1+1,n_2)+a(n_1-1,n_2) + a(n_1,n_2+1) + a(n_1,n_2-1) \right ] }
Bethe's approach for the coefficients Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a(n_1,n_2)}
are again plane wave but with unknown amplitudes Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A_1}
and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A_2}
:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a(n_1,n_2)=A_1e^{i(k_1n_1+k_2n_2)}+A_2e^{i(k_1n_2+k_2n_1)} }
The parameters Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A_1 } and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A_2 } are determined by the insertion into the Schrodinger equation. This gives the following amplitude ratio:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{A_1}{A_2}=e^{i \theta}=-\frac{e^{i(k_1+k_2)}+1-2e^{ik_1}}{e^{i(k_1+k_2)}+1-2e^{ik_2}} }
which gives:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a(n_1,n_2)=e^{i(k_1n_1+k_2n_2+\frac{1}{2}\theta_{12})}+e^{i(k_1n_2+k_2n_1+\frac{1}{2}\theta_{21})} }
Using periodic boundary conditions we obtain the wave numbers Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle k_1, k_2 } and the angle Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \theta = \theta_ {12} =- \theta_ {2,1} } satisfying the following equations:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2\cot \frac{\theta}{2}=\cot\frac{k_1}{2}-\cot\frac{k_2}{2} \qquad Nk_1=2\pi\lambda_1+\theta\qquad Nk_2=2\pi\lambda_2-\theta }
where the integers Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lambda_i = {0,1 ... N} } are called Bethe quantum numbers. Thus all eigenvectors for 2 flipped spin case is determined by all possible pairs that satisfy the equations. The energy is then given by:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E=E_{0}+J\sum_{j=1,2}\left (1-\cos(k_j)\right ) }
Case of r flipped spins
Eigenstates:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\Psi\rangle = \sum^N_{n1<n2<..<n_r}a(n_1,n_2,..,n_r)|n_1,n_2,..,n_r\rangle }
with coefficients:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a(n_1,..n_r)=\sum_{P\in S_r}\exp\left(i\sum^r_{j=1}k_{P_j}n_j+i\sum_{i<j}\theta_{P_iP_j} \right) }
The sum runs over all possible Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle r! } permutation of the numbers Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle {1, .., r} } . Inserting into the Schrödinger equation and applying the periodic boundary conditions lead to:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat} \cdot 2 \cot \frac{\theta_{ij}}{2}&=\cot\frac{k_i}{2}-\cot\frac{k_j}{2} &\qquad \text{where}\quad& i,j=1..r \\ Nk_i&=2\pi\lambda_i+\sum_{j \neq i}\theta_{ij}&&\lambda_i={1,..,N-1} \end{alignat} }
The eigenvectors are given with all combinations of Bethe quantum numbers Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (\lambda_1, .. \lambda_r) } satisfying the Bethe equations. The energy of the corresponding state is given by
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E=E_{0}+J\sum^r_{j=1}\left (1-\cos k_j \right) }