4th Week: Decays, Tunneling and Cross Sections: Difference between revisions
Jump to navigation
Jump to search
Moore Joell (talk | contribs) (New page: <math>E_{\alpha } = E_{center of mass} \frac{M_{product}+M_{reaction}}{M_{reaction}}, \; \; \; \; E_{center of mass} = E_{\alpha} \frac{M_{reaction}}{M_{reaction}+M_{product}}</math>) |
No edit summary |
||
| Line 1: | Line 1: | ||
=Nuclear Radiation= | |||
When looking at the table of nuclides it is obvious that the valley of stability is only a small percentage of all known nuclei. So most nuclei are considered unstable. To become stable these nuclides emit ionizing particles and radiation, resulting in a loss of energy from the original nuclei. This Process is called radioactive decay. | |||
==Alpha Decay== | |||
==Beta Decay== | |||
==Gamma Decay== | |||
<math>E_{\alpha } = E_{center of mass} \frac{M_{product}+M_{reaction}}{M_{reaction}}, | <math>E_{\alpha } = E_{center of mass} \frac{M_{product}+M_{reaction}}{M_{reaction}}, | ||
\; \; \; \; E_{center of mass} = E_{\alpha} \frac{M_{reaction}}{M_{reaction}+M_{product}}</math> | \; \; \; \; E_{center of mass} = E_{\alpha} \frac{M_{reaction}}{M_{reaction}+M_{product}}</math> | ||
Revision as of 13:59, 10 February 2009
Nuclear Radiation
When looking at the table of nuclides it is obvious that the valley of stability is only a small percentage of all known nuclei. So most nuclei are considered unstable. To become stable these nuclides emit ionizing particles and radiation, resulting in a loss of energy from the original nuclei. This Process is called radioactive decay.
Alpha Decay
Beta Decay
Gamma Decay
