Solution to Set 5: Difference between revisions

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'''Derive the dispersion relation <math>\omega^{\alpha} (k)\;</math> for this chain'''
'''Derive the dispersion relation <math>\omega^{\alpha} (k)\;</math> for this chain'''


* '''Index <math>\alpha = 1\;</math> for acoustic branch'''
=== Index <math>\alpha = 1\;</math> for acoustic branch ===


Potential Energy <math>U = 1, 2, 3, ... n \;</math>
Potential Energy <math>U = 1, 2, 3, ... n \;</math>
Line 55: Line 55:
<math>\Rightarrow \omega (k) = 2 \sqrt{ \frac{k}{m} } |sin(ka)|</math>
<math>\Rightarrow \omega (k) = 2 \sqrt{ \frac{k}{m} } |sin(ka)|</math>


* '''Index<math>\alpha = 2\;</math> for optical branch'''
=== '''Index<math>\alpha = 2\;</math> for optical branch''' ===


<math>u_m (t) = e^{ik(na)- \omega t} = e^{i k R_n} \;</math>  
<math>u_m (t) = e^{ik(na)- \omega t} = e^{i k R_n} \;</math>  

Revision as of 05:58, 2 March 2009

I have no idea what I'm doing - KimberlyWynne 03:11, 2 March 2009 (EST)

Diatomic harmonic chain

Problem 1

Given:

  • a chain of atoms
  • with alternating masses and
  • connected with elastic springs with constant
  • moving only in the x-direction

Chainatoms.jpg

Derive the dispersion relation for this chain

Index for acoustic branch

Potential Energy

Eigenvectors of Modes A and B (defined arbitrarily)

Band Matrix

Running waves through a solid

where

= distance on some coordinate system

Derive and get:

Index for optical branch

Dispersionrelation.jpg

Problem 2

Determine the speed of sound for this chain. What is the lowest frequency of long-wavelength sound corresponding to the optical branch?

From my lecture notes:

where = speed of sound

Problem 3

Sketch the motion of the atoms corresponding to the edge of the Brillouin zone, both for the optical and the acoustic branch.

Problem 4

Determine the Debye temperature for this system, and determine the form of the specific heat in the limits of high and low temperatures.

Problem 5

Consider low temperatures () and determine the wavelength of the most abundant phonons (Hint: note the analogy with Wien's Law!)