Delta Potential Born Approximation: Difference between revisions

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and the differential cross section is  
and the differential cross section is  


<math>\sigma(\theta)=\frac{m^2 g^2}{4\pi^2\hbar^4}</math>
<math>\sigma(\theta)=\frac{m^2 g^2}{4\pi^2\hbar^4}</math>.
 
As the distribution is isotropic, the total cross section is
 
<math>\sigma tot=4\pi\sigma=\frac{m^2 g^2}{\pi\hbar^4}</</math>.
   
   




i\hbar\frac{\partial \psi(\textbf{r},t)}{\partial t} = \left[ -\frac{\hbar^2}{2m}\nabla^2 + V(\textbf{r})\right]\psi(\textbf{r},t
i\hbar\frac{\partial \psi(\textbf{r},t)}{\partial t} = \left[ -\frac{\hbar^2}{2m}\nabla^2 + V(\textbf{r})\right]\psi(\textbf{r},t

Revision as of 21:40, 30 November 2009

Problem

Calculate the Born approximation to the differential and total cross sections for a particle of mass m off the -function potential .

Solution:

In Born approximation,

where with and are the wave vectors of the incident and scattered waves, respectively. Then

and the differential cross section is

.

As the distribution is isotropic, the total cross section is

.


i\hbar\frac{\partial \psi(\textbf{r},t)}{\partial t} = \left[ -\frac{\hbar^2}{2m}\nabla^2 + V(\textbf{r})\right]\psi(\textbf{r},t