Delta Potential Born Approximation: Difference between revisions
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As the distribution is isotropic, the total cross section is | As the distribution is isotropic, the total cross section is | ||
<math>\sigma tot=4\pi\sigma=\frac{m^2 g^2}{\pi\hbar^4} | <math>\sigma tot=4\pi\sigma=\frac{m^2 g^2}{\pi\hbar^4}</math>. | ||
i\hbar\frac{\partial \psi(\textbf{r},t)}{\partial t} = \left[ -\frac{\hbar^2}{2m}\nabla^2 + V(\textbf{r})\right]\psi(\textbf{r},t | i\hbar\frac{\partial \psi(\textbf{r},t)}{\partial t} = \left[ -\frac{\hbar^2}{2m}\nabla^2 + V(\textbf{r})\right]\psi(\textbf{r},t |
Revision as of 21:41, 30 November 2009
Problem
Calculate the Born approximation to the differential and total cross sections for a particle of mass m off the -function potential .
Solution:
In Born approximation,
where with and are the wave vectors of the incident and scattered waves, respectively. Then
and the differential cross section is
.
As the distribution is isotropic, the total cross section is
.
i\hbar\frac{\partial \psi(\textbf{r},t)}{\partial t} = \left[ -\frac{\hbar^2}{2m}\nabla^2 + V(\textbf{r})\right]\psi(\textbf{r},t