Delta Potential Born Approximation: Difference between revisions

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and the differential cross section is  
and the differential cross section is  


<math>\sigma(\theta)=\frac{m^2 g^2}{4\pi^2\hbar^4}</math>.
<math>\sigma(\theta)=|f_B(\theta)|^2=\frac{m^2 g^2}{4\pi^2\hbar^4}</math>.


As the distribution is isotropic, the total cross section is  
As the distribution is isotropic, the total cross section is  


<math>\sigma_t=4\pi\sigma=\frac{m^2 g^2}{\pi\hbar^4}</math>.
<math>\sigma_t=4\pi\sigma=\frac{m^2 g^2}{\pi\hbar^4}</math>.

Revision as of 19:36, 1 December 2009

Problem

Calculate the Born approximation to the differential and total cross sections for a particle of mass m off the -function potential .

Solution:

In Born approximation,

where with and are the wave vectors of the incident and scattered waves, respectively. Then

and the differential cross section is

.

As the distribution is isotropic, the total cross section is

.