Phy5646/Einstein coefficients example: Difference between revisions
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This example was taken from "Theory and Problems of Quantum Mechanics", Yoaf Peleg, <i>et al</i>, p. 296-297. | This example was taken from "Theory and Problems of Quantum Mechanics", Yoaf Peleg, <i>et al</i>, p. 296-297. | ||
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'''Problem:''' | '''Problem:''' | ||
A two-level system with eigenvalues <math>E_2 > E_1</math> is in the thermodynamics equilibrium with a heat reservoir at absolute temperature T. The system undergoes the following transitions: (i) Absorption <math>1 \rightarrow 2</math>, (ii) induced emission <math>2 \rightarrow 1</math>, and (iii) spontaneous emission <math>2 \rightarrow 1</math>. The transition rates for each of these processes are given by: | |||
A two-level system with eigenvalues <math>E_2 > E_1 \!</math> is in the thermodynamics equilibrium with a heat reservoir at absolute temperature <math> T \!</math>. The system undergoes the following transitions: (i) Absorption <math>1 \rightarrow 2</math>, (ii) induced emission <math>2 \rightarrow 1</math>, and (iii) spontaneous emission <math>2 \rightarrow 1</math>. The transition rates for each of these processes are given by: | |||
:<math> | :<math> | ||
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</math> | </math> | ||
where <math>u(w_{21})</math> is the energy distribution of the radiation field, <math>P_j</math> is the probability of finding the system in level j of degeneracy <math>g_j | where <math>u(w_{21}) \!</math> is the energy distribution of the radiation field, <math>P_j \!</math> is the probability of finding the system in level <math> j \!</math> of degeneracy <math>g_j (j=1,2)\!</math>, and <math>A_{12}\!</math> and <math>B_{12}\!</math> are the Einstein coefficients for spontaneous and induced emission, respectively. (a) Calculate the probabilities <math>P_1\!</math> and <math>P_2\!</math> under equilibrium conditions. (b) Use the rates together with Planck's formula for black body radiation to show that | ||
:<math> | :<math> | ||
g_1 B_{21} = g_2 B_{12} | g_1 B_{21} = g_2 B_{12} | ||
</math> | \!</math> | ||
:<math> | :<math> | ||
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</math> | </math> | ||
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'''Solution (a):''' | '''Solution (a):''' | ||
Under thermal equilibrium at absolute temperature T, the probability of finding the system in one of its stationary states |i> with and eigenvalue <math>\epsilon_i</math> is proportional to the Boltzmann factor <math>e^{\frac{ | Under thermal equilibrium at absolute temperature <math> T \!</math>, the probability of finding the system in one of its stationary states <math> |i\rangle \!</math> with and eigenvalue <math>\epsilon_i\!</math> is proportional to the Boltzmann factor <math>e^{-\frac{\epsilon_i}{kT}}</math>. In this problem <math>\epsilon_i\!</math> assumes the value <math>E_1\!</math>, <math>E_2\!</math> with respective degeneracies <math>g_i = g_1, g_2 \!</math> (a two-level system). Therefore, | ||
:<math> | :<math> | ||
P_1=C g_1 e^{\frac{ | P_1=C g_1 e^{-\frac{E_1}{kT}} | ||
</math> | </math> | ||
:<math> | :<math> | ||
P_2=C g_2 e^{\frac{ | P_2=C g_2 e^{-\frac{E_2}{kT}} | ||
</math> | </math> | ||
where <math> C \!</math> is the normalization constant. Since <math>P_1 + P_2 =1 \!</math>, we immediately find that | |||
where C is the normalization constant. Since <math>P_1 + P_2 =1</math>, we immediately find that | |||
:<math> | :<math> | ||
C^{-1} = g_1 e^{\frac{ | C^{-1} = g_1 e^{-\frac{E_1}{kT}} + g_2 e^{-\frac{E_2}{kT}} | ||
</math> | </math> | ||
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'''Solution (b):''' | '''Solution (b):''' | ||
Suppose that a larger number of systems, such as in part (a), form a closed cavity that is kept in equilibrium with its own thermal radiation at constant temperature T. In this case, | Suppose that a larger number of systems, such as in part (a), form a closed cavity that is kept in equilibrium with its own thermal radiation at constant temperature <math> T \!</math>. In this case, | ||
:<math> | :<math> | ||
W_{21}^{abs} = W_{12}^{ind} + W_{12}^{spon} | W_{21}^{abs} = W_{12}^{ind} + W_{12}^{spon} | ||
</math> | </math> | ||
Then from the transitions rates, we obtain | Then from the transitions rates, we obtain | ||
:<math> | :<math> | ||
P_1 B_{21} u(w_{21}) = P_2 B_{12} u(w_{21}) + P_2 A_{12} | P_1 B_{21} u(w_{21}) = P_2 B_{12} u(w_{21}) + P_2 A_{12} | ||
</math> | \!</math> | ||
or from the last result in part (a) | or from the last result in part (a) | ||
:<math> | :<math> | ||
g_1 B_{21} (e^{\frac{\hbar w_{21}}{kT}} - \frac{g_2 B_{12}}{g_1 B_{21}}) \frac{\hbar w_{21}^3}{\pi^2 c^3}= g_2 A_{12}(e^{\frac{\hbar w_{21}}{kT}} - 1) | g_1 B_{21} (e^{\frac{\hbar w_{21}}{kT}} - \frac{g_2 B_{12}}{g_1 B_{21}}) \frac{\hbar w_{21}^3}{\pi^2 c^3}= g_2 A_{12}(e^{\frac{\hbar w_{21}}{kT}} - 1) | ||
</math> | </math> | ||
Hence, | Hence, | ||
:<math> | :<math> | ||
g_1 B_{21} =g_2 B_{12} | g_1 B_{21} =g_2 B_{12} | ||
</math> | \!</math> | ||
:<math> | :<math> | ||
A_{12}= \frac{\hbar w_{21}^3}{\pi^2 c^3} B_{12} | A_{12}= \frac{\hbar w_{21}^3}{\pi^2 c^3} B_{12} | ||
</math> | </math> |
Latest revision as of 22:05, 24 April 2010
(Submitted by Team 1)
This example was taken from "Theory and Problems of Quantum Mechanics", Yoaf Peleg, et al, p. 296-297.
Problem:
A two-level system with eigenvalues is in the thermodynamics equilibrium with a heat reservoir at absolute temperature . The system undergoes the following transitions: (i) Absorption , (ii) induced emission , and (iii) spontaneous emission . The transition rates for each of these processes are given by:
where Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle u(w_{21}) \!} is the energy distribution of the radiation field, Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle P_j \!} is the probability of finding the system in level Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle j \!} of degeneracy Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g_j (j=1,2)\!} , and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A_{12}\!} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B_{12}\!} are the Einstein coefficients for spontaneous and induced emission, respectively. (a) Calculate the probabilities Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle P_1\!} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle P_2\!} under equilibrium conditions. (b) Use the rates together with Planck's formula for black body radiation to show that
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g_1 B_{21} = g_2 B_{12} \!}
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A_{12}= \frac{\hbar w_{21}^3}{\pi^2 c^3} B_{12} }
Solution (a):
Under thermal equilibrium at absolute temperature Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T \!} , the probability of finding the system in one of its stationary states Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |i\rangle \!} with and eigenvalue Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \epsilon_i\!} is proportional to the Boltzmann factor Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e^{-\frac{\epsilon_i}{kT}}} . In this problem Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \epsilon_i\!} assumes the value Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E_1\!} , Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E_2\!} with respective degeneracies Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g_i = g_1, g_2 \!} (a two-level system). Therefore,
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle P_1=C g_1 e^{-\frac{E_1}{kT}} }
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle P_2=C g_2 e^{-\frac{E_2}{kT}} }
where Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle C \!} is the normalization constant. Since Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle P_1 + P_2 =1 \!} , we immediately find that
Since , we have
Solution (b):
Suppose that a larger number of systems, such as in part (a), form a closed cavity that is kept in equilibrium with its own thermal radiation at constant temperature . In this case,
Then from the transitions rates, we obtain
or from the last result in part (a)
Hence,