(Submitted by team 1. Based on problem 3.19 in Schaum's Theory and problems of Quantum Mechanics)
Consider a particle of mass m in a three dimensional potential:
Using the Schroedinger's equation show that we can treat the problem like three independent one-dimensional problems. Relate the energy of the three-dimensional state to the effective energies of one-dimensional problem.
The Schroedinger's equation takes the form:

Assuming that
can be write like:

So,
![{\displaystyle {\begin{aligned}-{\frac {\hbar ^{2}}{2m}}\left[{\frac {d^{2}\Phi (x)}{dx^{2}}}\Delta (y)\Omega (z)+\Phi (x){\frac {d^{2}\Delta (y)}{dy^{2}}}\Omega (z)+\Phi (x)\Delta (y){\frac {d^{2}\Omega (z)}{dz^{2}}}\right]\\+\left[X(x)+Y(y)+Z(z)\right]\Phi (x)\Delta (y)\Omega (z)&=E\Phi (x)\Delta (y)\Omega (z)\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/763c2e10d0e6359f87db6bf0e6a1f819a576e44d)
Dividing by

Perfectly we can separate the right hand side in three parts, where only one depends of
, only one of
and only one of
. Then each of these parts must be equal to a constant. So:



where
,
and
are constant and
Hence the three-dimensional problem has been divided in three one-dimensional problems where the total energy
is the sum of the energies
,
and
in each dimension.