DetailedBalance
Consider a transition from between two states of the nucleus with spins and , respectively. The transition probability is proportional to the squared matrix element where is a hermitian tensor operator of rank responsible for the process. Define the reduced transition probability
as a sum of squared matrix elements over final projections and operator projections .
a) Express in terms of the reduced matrix element Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (f|| T_{\lambda}|| i)}
and show that it does not depend on the initial projection Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle M_i}
.
b) Establish the detailed balance between the reduced transition probabilities of the direct Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle i \rightarrow f} , and inverse Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f \rightarrow i} processes.
SOLUTION:
a) According to the Wigner-Eckert theorem, the entire dependence of the matrix element of a tensor operator on the magnetic quantum numbers is concentrated in the vector coupling coefficients,
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle J_f M_f| T_{\lambda \mu}| J_i M_i \rangle = (-)^{J_f-M_f} \left( \begin{array}{lll} J_f & \lambda & J_i \\ -M_f & \mu & M_i \end{array} \right) (f|| T_{\lambda}|| i) }
We obtain the rate by squaring this and summing over and
Using the orthogonality condition:
Which leads us to our final result:
It is obvious that this result does not depend on