(Submitted by team 1. Based on problem 3.19 in Schaum's Theory and problems of Quantum Mechanics)
Consider a particle of mass m in a three dimensional potential:
Using the Schroedinger's equation show that we can treat the problem like three independent one-dimensional problems. Relate the energy of the three-dimensional state to the effective energies of one-dimensional problem.
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The Schroedinger's equation takes the form:

Assuming that
can be write like:

So,
![{\displaystyle -{\frac {\hbar ^{2}}{2m}}\left[{\frac {d^{2}\Phi (x)}{dx^{2}}}\Delta (y)\Omega (z)+\Phi (x){\frac {d^{2}\Delta (y)}{dy^{2}}}\Omega (z)+\Phi (x)\Delta (y){\frac {d^{2}\Omega (z)}{dz^{2}}}\right]+\left[X(x)+Y(y)+Z(z)\right]\Phi (x)\Delta (y)\Omega (z)=E\Phi (x)\Delta (y)\Omega (z)}](https://wikimedia.org/api/rest_v1/media/math/render/svg/4bd5010a2c0be85e480a988ba10d64451d54a9fd)
Dividing by

Perfectly we can separate the right hand side in three parts, where only one depends of x, only one of y and only one of z. Then each of these parts must be equal to a constant. So:



where E_x, E_y and E_z are constant and
Hence the three-dimensional problem has been divided in three one-dimensional problems where the total energy E is the sum of the energies
,
and
in each dimension.