Solution to Set 4: Difference between revisions
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Cu, density <math> \rho= 8.885{g\over cm^3}</math>, atomic mass <math> m_a = 63.57 amu</math>, fcc structure | Cu, density <math> \rho= 8.885{g\over cm^3}</math>, atomic mass <math> m_a = 63.57 amu</math>, fcc structure | ||
a. In <math>1 m^3</math>, the number of moles is | |||
<math>8.885{g\over cm^3} x {1 cm^3/over 1 x 10^-6 m^3} x {1 mol/over 63.55 g} = 1.40 x 10^5 {mol/over m^3}</math> | |||
Revision as of 17:20, 20 February 2009
Problem 1
Cu, density , atomic mass , fcc structure
a. In , the number of moles is
