Solution to Set 4: Difference between revisions
Jump to navigation
Jump to search
| Line 4: | Line 4: | ||
a. In <math>1 m^3</math>, the number of moles is | a. In <math>1 m^3</math>, the number of moles is | ||
<math>8. | <math>{8.885g\over cm^3} {1\over 1.0 × 10^-6} {1 mol\over 63.55 g} = 1.40 × 10^5</math> | ||
Revision as of 17:33, 20 February 2009
Problem 1
Cu, density , atomic mass , fcc structure
a. In , the number of moles is Failed to parse (syntax error): {\displaystyle {8.885g\over cm^3} {1\over 1.0 × 10^-6} {1 mol\over 63.55 g} = 1.40 × 10^5}
