Solution to Set 4: Difference between revisions

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(New page: 1. Cu, density <math>p=8.885 g cm^-3</math>, atomic mass <math>m_a=63.57 amu</math>, fcc structure a. In <math>1 m^3</math> the number of moles is <math>(8.885 g cm^-3)(1/e{-6} m^-3)(63.5...)
 
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1. Cu, density <math>p=8.885 g cm^-3</math>, atomic mass <math>m_a=63.57 amu</math>, fcc structure
1. Cu, density <math>p=8.885</math>g cm^(-3), atomic mass <math>m_a=63.57 amu</math>, fcc structure


a. In <math>1 m^3</math> the number of moles is
a. In <math>1 m^3</math> the number of moles is
<math>(8.885 g cm^-3)(1/e{-6} m^-3)(63.55 g^-1)=1.40/e{5} mol m^-3</math>
<math>(8.885 g cm^-3)(1/e{-6} m^-3)(63.55 g^-1)=1.40/e{5} mol m^-3</math>

Revision as of 16:23, 20 February 2009

1. Cu, density g cm^(-3), atomic mass , fcc structure

a. In the number of moles is