Solution to Set 4: Difference between revisions
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a. In <math>1 m^3</math> the number of moles is | a. In <math>1 m^3</math> the number of moles is | ||
<math>(8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)={{nowrap|''1.40'' × 10<sup>''-6''</sub>}} | <math>(8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)=</math>{{nowrap|''1.40'' × 10<sup>''-6''</sub>}} | ||
Revision as of 16:29, 20 February 2009
1. Cu, density , atomic mass , fcc structure
a. In the number of moles is Failed to parse (unknown function "\e"): {\displaystyle (8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)=} Template:Nowrap
