Solution to Set 4: Difference between revisions

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\providecommand{\e}[1]{\ensuremath{\times 10^{#1}}}
1. Cu, density <math>p=8.885 g cm^(-3)</math>, atomic mass <math>m_a=63.57 amu</math>, fcc structure
1. Cu, density <math>p=8.885 g cm^(-3)</math>, atomic mass <math>m_a=63.57 amu</math>, fcc structure


a. In <math>1 m^3</math> the number of moles is
a. In <math>1 m^3</math> the number of moles is
<math>(8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)=1.40\e{5} mol m^(-3)</math>
<math>(8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)=1.40\e{5} mol m^(-3)</math>

Revision as of 16:25, 20 February 2009

\providecommand{\e}[1]{\ensuremath{\times 10^{#1}}}

1. Cu, density , atomic mass , fcc structure

a. In the number of moles is Failed to parse (unknown function "\e"): {\displaystyle (8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)=1.40\e{5} mol m^(-3)}