Solution to Set 4: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
Line 1: | Line 1: | ||
\providecommand{\e}[1]{\ensuremath{\times 10^{#1}}} | |||
1. Cu, density <math>p=8.885 g cm^(-3)</math>, atomic mass <math>m_a=63.57 amu</math>, fcc structure | 1. Cu, density <math>p=8.885 g cm^(-3)</math>, atomic mass <math>m_a=63.57 amu</math>, fcc structure | ||
a. In <math>1 m^3</math> the number of moles is | a. In <math>1 m^3</math> the number of moles is | ||
<math>(8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)=1.40\e{5} mol m^(-3)</math> | <math>(8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)=1.40\e{5} mol m^(-3)</math> |
Revision as of 16:25, 20 February 2009
\providecommand{\e}[1]{\ensuremath{\times 10^{#1}}}
1. Cu, density , atomic mass , fcc structure
a. In the number of moles is Failed to parse (unknown function "\e"): {\displaystyle (8.885 g cm^-3)(1\e{-6} m^-3)(63.55 g^-1)=1.40\e{5} mol m^(-3)}