Solution to Set 4: Difference between revisions
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a. In <math>1 m^3</math> the number of moles is | a. In <math>1 m^3</math> the number of moles is | ||
<math>(8.885 g cm^-3)(1 | <math>(8.885 g cm^-3)({{nowrap|''1'' × 10<sup>''-6''</sub>}}(63.55 g^-1)={{nowrap|''1.40'' × 10<sup>''-6''</sub>}}</math> | ||
Revision as of 16:30, 20 February 2009
1. Cu, density , atomic mass , fcc structure
a. In the number of moles is Failed to parse (syntax error): {\displaystyle (8.885 g cm^-3)({{nowrap|''1'' × 10<sup>''-6''</sub>}}(63.55 g^-1)={{nowrap|''1.40'' × 10<sup>''-6''</sub>}}}
