Solution to Set 4: Difference between revisions
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a. In <math>1 m^3</math>, the number of moles is | a. In <math>1 m^3</math>, the number of moles is | ||
<math>8.885{g\over cm^3} {1\over 1.0 × 10-6}</math> | <math>8.885{g\over cm^3} {1\over 1.0 × 10^-6} {1 mol\over 63.55 g} = 1.40 × 10^5</math> | ||
Revision as of 17:33, 20 February 2009
Problem 1
Cu, density , atomic mass , fcc structure
a. In , the number of moles is Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 8.885{g\over cm^3} {1\over 1.0 × 10^-6} {1 mol\over 63.55 g} = 1.40 × 10^5}
