Linear Vector Spaces and Operators: Difference between revisions
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Because <math>\lambda\neq\lambda',</math>, we conclude that <math>\langle\phi|\psi\rangle = 0;</math> i.e., <math>|\psi\rangle</math> and <math>|\phi\rangle</math> are mutually orthogonal. | Because <math>\lambda\neq\lambda',</math>, we conclude that <math>\langle\phi|\psi\rangle = 0;</math> i.e., <math>|\psi\rangle</math> and <math>|\phi\rangle</math> are mutually orthogonal. | ||
==Projection | == Projection Operators == | ||
An operator<math>\hat{P}</math> is said to be a | An operator<math>\hat{P}</math> is said to be a projection operator if it is Hermitian and equal to its own square. Thus, <math>\hat{P}=\hat{P}^{\dagger}</math> and <math>\hat{P}=\hat{P}^2.</math> Such operators are called projection operators because they "project" the vector that they act on onto the "direction" of another vector. The projection operator corresponding to the ket <math>|x\rangle</math> can be written as <math>\hat{P} = |x\rangle\langle x|</math>. | ||
Thus,<math>\hat{P}</math> | The completion relation is given by <math>\Sigma |x\rangle\langle x| = I </math> or, <math>\Sigma P_x \!= I</math> | ||
For any vector <math>|\psi\rangle</math>, | |||
<math>P_x|V\rangle = |x\rangle\langle x|V\rangle = |x\rangle v_x</math> | |||
The projection operator selects the component of <math>|V\rangle</math> in the direction of <math>|x\rangle</math> | |||
Projection operators possess the following proerties. | |||
'''(1) The product of two commuting projection operators <math>\hat{P}_1</math> and <math>\hat{P}_2</math> is also a projection operator.''' | |||
''Proof:'' | |||
<math>(\hat{P}_1\hat{P}_2)^{\dagger} =\hat{P}_2^{\dagger}\hat{P}_1^{\dagger} = \hat{P}_2\hat{P}_1 =\hat{P}_1\hat{P}_2 </math> | |||
and | |||
<math>(\hat{P}_1\hat{P}_2)^2 = \hat{P}_1\hat{P}_2 \hat{P}_1\hat{P}_2 =\hat{P}_1^2\hat{P}_2^2= \hat{P}_1\hat{P}_2.</math> | |||
2. The sum of two or more Projection operators is not a Projection operator in general. The sum is a Projection operator iff the operators are mutually orthogonal. | |||
3. Two Projection operators are said to be orthogonal if the product of the two operators is zero. |
Revision as of 16:24, 2 July 2013
Quantum mechanics can be conveniently formulated in the language of abstract state vectors, from which the various representations (wave mechanics, matrix mechanics, Schrödinger, Heisenberg and interaction pictures, etc.) can be derived. A formulation of quantum mechanics in terms of linear vector spaces hinges on the fact that the Schrödinger equation is linear. An operator is a mathematical operation performed on a vector belonging to a linear vector space, the result of which is another vector belonging to the same linear vector space.
The Vector (Ket) Space
In quantum mechanics a physical state is represented by a state vector in a complex vector space and have all the properties described above. Following Dirac, we call such a vector a "ket", denoted by Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\alpha\rangle} . This state ket is postulated to contain complete information about the physical state (i.e. everything we are allowed to ask about the state is contained in the ket). The complex linear vector spaces that we work with in quantum mechanics are usually infinite dimensional. In this case, the vector space in question is known as a Hilbert space after D. Hilbert, who studied vector spaces in infinite dimensions.
One of the postulates of quantum mechanics is that Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\alpha\rangle} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c|\alpha\rangle,} with Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c\neq 0,} represent the same physical state. In other words, only the ”direction” in vector space is of significance.
The Dual (Bra) Space
The vector space we have been dealing with is a ket space. We now introduce the notion of a "bra" space, a vector space ”dual to” the ket space. We postulate that corresponding to every ket Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\alpha\rangle} there exists a bra denoted by Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle\alpha |} in this dual or bra space. The bra space is spanned by a set of bra vectors Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left \{\langle\alpha |\right \}} which correspond to the set of kets Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left \{|\alpha\rangle\right \}.} Mathematically, the dual space is a set of linear functions Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle\beta|: V \rightarrow C } that act on the members of the corresponding vector space (kets) where Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle V} is the vector space and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle C} is the set of complex numbers.
There is a one to one correspondence between the members of a ket space and those of the corresponding bra space, Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\alpha\rangle\leftrightarrow\langle\alpha |,} where Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \leftrightarrow} stands for dual correspondence. Roughly speaking, we can regard the bra space as some kind of "mirror image" of the ket space.
The bra dual to Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c|\alpha\rangle} is postulated to be Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c^{\ast}\langle\alpha |} , not Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c\langle\alpha |,} which is a very important point to note. More generally, we have
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c_{\alpha}|\alpha\rangle+c_{\beta}|\beta\rangle+\cdots\leftrightarrow c^{\ast}_{\alpha}\langle\alpha |+c^{\ast}_{\beta}\langle\beta |+\cdots}
Linear Independence and Bases
Consider Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle N\!} vectors (ket states) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |1\rangle } ,Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |2\rangle,\ldots,|N\rangle.} They are linearly independent if the relation Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sum_{i=1}^{N}c_i|i\rangle=0 } necessarily implies Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c_i=0 \!} for Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle i = 1,2,...,N\!} . They can be used as basis in a vector space, and decomposition of any vector in terms of basis vectors in unique.
While any set of linearly independent vectors can be used as a basis, normally the discussion is greatly simplified if the basis is orthonormal, i.e Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle i|j \rangle=\delta_{ij}} . The action of an operator is completely known once its action on each of the basis vectors of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathit{V}} is given.
The Hilbert Space
A Hilbert space Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle H\!} consisting of a set of vectors Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \psi,\phi,\chi,\ldots\!} and a set of scalars Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a,b,c,\ldots\!} obeys the following properties.
(a) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle H\!}
is a linear vector space. It obeys all the properties of a linear vector space as mentioned in the previous section.
(b) The scalar product defined in Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle H\!}
is strictly positive. The scalar product of one element Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi\!}
with another element Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \psi\!}
is a complex number, denoted by Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle\phi|\psi\rangle}
. This scalar satisfies the following properties.
1. The scalar product of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi\!} with Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \psi\!} is same as the complex conjugate of the scalar product of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \psi\!} with Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi\!} .
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle\phi|\psi\rangle=\langle\psi|\phi\rangle^{\ast}}
2. The scalar product of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \psi\!} with Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi\!} is linear with respect to Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi\!} .
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle\psi|a\psi_{1} + b\psi_{2}\rangle=a\langle\psi|\phi_{1}\rangle + b\langle\psi|\phi_{2}\rangle}
3. The scalar product of a state vector Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \psi\!} with itself is a positive real number.
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \langle\psi|\psi\rangle=|\psi|^2\geq 0 }
Schwartz Inequality
For two states Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\psi\rangle} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\phi\rangle} belonging to a linear vector space, the following theorem, known as the Schwartz inequality, holds:
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\langle\psi|\phi\rangle|^{2}\leq\langle\psi|\psi\rangle\langle\phi|\phi\rangle}
If the vectors Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\psi\rangle} and are linearly dependent, i.e. = then the above relation becomes an equality.
Proof: Let and be arbitrary vectors in the vector space The inequality is trivial in the case that at least one of and so we will consider the case that both are nonzero. Let be a complex number. Then
The above expression is valid for any number . The right-hand side of the above expression is minimized if we choose
Using this value of we obtain
or
Linear Operators
Let be a linear vector space. A linear operator is an operation, denoted by that maps a given ket vector in to a different vector in the same space, and has the property that
In addition, linear operators obey the following properties.
(1) If for every , then is equal to .
(2) Commutative law:
(3) Associative law:
(4) Multiplication of operators:
(5) There exists an identity operator such that
(6) For any operator there exists an inverse operator such that
The Hermitian Adjoint
The dual vector to is where is known as the Hermitian adjoint of which is itself a linear operator. The properties obeyed by Hermitian adjoints are as follows.
(1)
(2) For any complex number
(3)
(4)
(5) For any complex number
(6)
(7)
Special Linear Operators in Quantum Mechanics
Hermitian Operator: An operator is called Hermitian if All physical observables in quantum mechanics are represented by Hermitian operators.
Antihermitian operator: An operator is called anti-Hermitian if
Every operator can be decomposed uniquely in terms of a Hermitian and an anti-Hermitian part: .
Unitary Operator: An operator is called unitary if there exits an unique and is equal to , i.e., . An important property of unitary operators is that they preserve the norm of a vector, which in quantum mechanics refers to the conservation of probability under physical operations.
Antilinear operator: An operator is called antilinear if for any two vectors and and for any two complex numbers and , All operators of importance in quantum mechanics are linear, with one important exception - the time reversal operator is an antilinear operator.
Theorem on Eigenvalues and Eigenstates of Hermitian Operator
We will now prove that the eigenvalues of Hermitian operators are real and that two eigenvectors of a Hermitian operator that correspond to different eigenvalues are orthogonal.
Proof: Consider an eigenstate of a Hermitian operator , corresponding to an eigenvalue i.e.,
Taking the Hermitian adjoint of both sides, and using the fact that , we get
Taking the scalar product of the first equation with and of the second with , we get
Because is not a null vector, we conclude that i.e, is real.
To prove the second part of the theorem, consider another eigenstate with a different eigenvalue i.e.,
Taking the scalar product of the first equation with and of the second equation withn , we get
.
Because , we conclude that i.e., and are mutually orthogonal.
Projection Operators
An operator is said to be a projection operator if it is Hermitian and equal to its own square. Thus, and Such operators are called projection operators because they "project" the vector that they act on onto the "direction" of another vector. The projection operator corresponding to the ket can be written as . The completion relation is given by or,
For any vector ,
The projection operator selects the component of in the direction of
Projection operators possess the following proerties.
(1) The product of two commuting projection operators and is also a projection operator.
Proof:
and
2. The sum of two or more Projection operators is not a Projection operator in general. The sum is a Projection operator iff the operators are mutually orthogonal.
3. Two Projection operators are said to be orthogonal if the product of the two operators is zero.