Time Evolution of Expectation Values and Ehrenfest's Theorem: Difference between revisions
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<math>\frac{d\langle\hat{O}(t)\rangle}{dt}=\frac{i}{\hbar}\langle\Psi(t)|\hat{H}(t)\hat{O}(t)|\Psi(t)\rangle-\frac{i}{\hbar}\langle\Psi(t)|\hat{O}(t)\hat{H}(t)|\Psi(t)\rangle+\langle\frac{d\hat{O}(t)}{dt}\rangle</math> | <math>\frac{d\langle\hat{O}(t)\rangle}{dt}=\frac{i}{\hbar}\langle\Psi(t)|\hat{H}(t)\hat{O}(t)|\Psi(t)\rangle-\frac{i}{\hbar}\langle\Psi(t)|\hat{O}(t)\hat{H}(t)|\Psi(t)\rangle+\langle\frac{d\hat{O}(t)}{dt}\rangle</math> | ||
<math>=\frac{i}{\hbar}\langle | <math>=\frac{i}{\hbar}\langle[\hat{H}(t),\hat{O}(t)]\rangle+\langle\frac{d\hat{O}(t)}{dt}\rangle.</math> | ||
This formula is of the utmost importance in all facets of quantum mechanics. | This formula is of the utmost importance in all facets of quantum mechanics. |
Revision as of 16:16, 25 July 2013
Time Evolution of Expecation Values
Having described in the previous section how the state vector of a system evolves in time, we may now derive a formula for the time evolution of the expectation value of an operator. Given an operator we know that its expectation value is given by If we take the time derivative of this expectation value, we get
We now use the Schrödinger equation and its dual to write this as
This formula is of the utmost importance in all facets of quantum mechanics.