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We now write down the Cartesian components of the angular momentum operator in spherical coordinates.  We will make use of this result later in determining the eigenfunctions of the angular momentum squared and of one of its components.
We now write down the Cartesian components of the angular momentum operator in spherical coordinates.  We will make use of this result later in determining the eigenfunctions of the angular momentum squared and of one of its components.


The Cartesian coordinates <math>x,\!</math <math>y,\!</math> and <math>z\!</math> can be written in terms of the spherical coordinates <math>r,\!</math> <math>\theta,\!</math> and <math>\phi\!</math> as follows:
The Cartesian coordinates <math>x,\!</math> <math>y,\!</math> and <math>z\!</math> can be written in terms of the spherical coordinates <math>r,\!</math> <math>\theta,\!</math> and <math>\phi\!</math> as follows:


<math>x=r\sin\theta\cos\phi,\!</math> <math>y=r\sin\theta\sin\phi,\!</math> <math>z=r\cos\theta\!</math>
<math>x=r\sin\theta\cos\phi,\!</math> <math>y=r\sin\theta\sin\phi,\!</math> <math>z=r\cos\theta\!</math>


Denote the state <math> \langle \mathbf{r} \!\, | = \langle \mathbf{r}\! \,  \theta \phi |  </math>
Let us start with the <math>x\!</math> component of the angular momentum, <math>\hat{L}_x.</math> In Cartesian coordinates, this is


If you choose <math> \alpha \! </math> along the z-axis then the only coordinate that will change is phi such that <math> \phi \rightarrow \phi + \alpha </math>.  Now the state is written as:
<math>\hat{L}_x=-i\hbar\left (y\frac{\partial}{\partial z}-z\frac{\partial}{\partial y}\right ).</math>


<math> \langle \mathbf{r}\! \, \theta \phi | \left(1 + \frac{i}{\hbar} \alpha L_{z}\right) = \langle \mathbf{r} \! \, \theta \phi + \alpha | </math>
If we make use of the chain rule, then we obtain


Working to first order in alpha the right hand side becomes:
<math>\hat{L}_{x} = -i\hbar\left( -\sin\phi \frac{\partial}{\partial \theta} \, -\cot\theta\cos\phi \frac{\partial}{\partial\phi} \! \right).</math>


<math> \langle \mathbf{r}\! \, \theta \phi | + \alpha \frac{\partial}{\partial \phi} \langle \mathbf{r}\! \, \theta \phi | </math>
Similarly, the <math>y\!</math> and <math>z\!</math> components may be found to be


Therefore <math> L_{z} = \frac{\hbar}{i} \frac{\partial}{\partial \phi} </math>
<math>\hat{L}_{y} = -i\hbar\left(\cos\phi \frac{\partial}{\partial\theta} - \cot\theta\sin\phi \frac{\partial}{\partial\phi} \! \right) </math>


and


Now choose <math> \alpha \! </math> along the x-axis then the cartesian coordinates are changed such that:
<math>\hat{L}_{z} = -i\hbar\frac{\partial}{\partial \phi}.</math>
<math> x \rightarrow x  \!  </math> ,
<math> y \rightarrow y - \alpha z  \!</math>, and
<math> z \rightarrow z + \alpha y \! </math>,
 
from these transformations it can be determined that <math> \delta \theta = -\alpha\sin\phi \! </math> since <math> \delta z = \alpha y \! </math>
and since x does not change it can be determined that <math> \delta \phi  = -\alpha\cot\theta \cos\phi \! </math>.
 
This means that the original state is now written as:
<math> \langle \mathbf{r}\! \, \theta \phi | \left(1 + \frac{i}{\hbar} \alpha L_{x}\right) = \langle \mathbf{r} \! \, \,\theta - \alpha\sin\phi \,  \phi - \alpha\cot\theta\cos\phi | </math>
 
Expanding the right hand side of the above equation as before to the first order of alpha the whole equation becomes:
<math> \langle \mathbf{r}\! \, \theta \phi | L_{x} = \frac{\hbar}{i} \left( -\sin\phi \frac{\partial}{\partial \theta} \, -\cot\theta\cos\phi \frac{\partial}{\partial\phi} \! \right)  \langle \mathbf{r}\! \, \theta \phi | </math>
 
Therfore <math> L_{x} = \frac{\hbar}{i}\left( -\sin\phi \frac{\partial}{\partial \theta} \, -\cot\theta\cos\phi \frac{\partial}{\partial\phi} \! \right) </math>
 
Using the same techinque, choose <math> \alpha \! </math> along the y-axis and the coordinates will change in a similar fashion such that it can be shown that <math> L_{y} = \frac{\hbar}{i} \left(\cos\phi \frac{\partial}{\partial\theta} - \cot\theta\sin\phi \frac{\partial}{\partial\phi} \! \right) </math>


==Problem==
==Problem==

Revision as of 22:25, 28 August 2013

Quantum Mechanics A
SchrodEq.png
Schrödinger Equation
The most fundamental equation of quantum mechanics; given a Hamiltonian Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathcal{H}} , it describes how a state Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle |\Psi\rangle} evolves in time.
Basic Concepts and Theory of Motion
UV Catastrophe (Black-Body Radiation)
Photoelectric Effect
Stability of Matter
Double Slit Experiment
Stern-Gerlach Experiment
The Principle of Complementarity
The Correspondence Principle
The Philosophy of Quantum Theory
Brief Derivation of Schrödinger Equation
Relation Between the Wave Function and Probability Density
Stationary States
Heisenberg Uncertainty Principle
Some Consequences of the Uncertainty Principle
Linear Vector Spaces and Operators
Commutation Relations and Simultaneous Eigenvalues
The Schrödinger Equation in Dirac Notation
Transformations of Operators and Symmetry
Time Evolution of Expectation Values and Ehrenfest's Theorem
One-Dimensional Bound States
Oscillation Theorem
The Dirac Delta Function Potential
Scattering States, Transmission and Reflection
Motion in a Periodic Potential
Summary of One-Dimensional Systems
Harmonic Oscillator Spectrum and Eigenstates
Analytical Method for Solving the Simple Harmonic Oscillator
Coherent States
Charged Particles in an Electromagnetic Field
WKB Approximation
The Heisenberg Picture: Equations of Motion for Operators
The Interaction Picture
The Virial Theorem
Commutation Relations
Angular Momentum as a Generator of Rotations in 3D
Spherical Coordinates
Eigenvalue Quantization
Orbital Angular Momentum Eigenfunctions
General Formalism
Free Particle in Spherical Coordinates
Spherical Well
Isotropic Harmonic Oscillator
Hydrogen Atom
WKB in Spherical Coordinates
Feynman Path Integrals
The Free-Particle Propagator
Propagator for the Harmonic Oscillator
Differential Cross Section and the Green's Function Formulation of Scattering
Central Potential Scattering and Phase Shifts
Coulomb Potential Scattering

We now write down the Cartesian components of the angular momentum operator in spherical coordinates. We will make use of this result later in determining the eigenfunctions of the angular momentum squared and of one of its components.

The Cartesian coordinates Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x,\!} Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y,\!} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle z\!} can be written in terms of the spherical coordinates Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle r,\!} Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \theta,\!} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi\!} as follows:

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=r\sin\theta\cos\phi,\!} Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y=r\sin\theta\sin\phi,\!} Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle z=r\cos\theta\!}

Let us start with the Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x\!} component of the angular momentum, Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \hat{L}_x.} In Cartesian coordinates, this is

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \hat{L}_x=-i\hbar\left (y\frac{\partial}{\partial z}-z\frac{\partial}{\partial y}\right ).}

If we make use of the chain rule, then we obtain

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \hat{L}_{x} = -i\hbar\left( -\sin\phi \frac{\partial}{\partial \theta} \, -\cot\theta\cos\phi \frac{\partial}{\partial\phi} \! \right).}

Similarly, the Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y\!} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle z\!} components may be found to be

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \hat{L}_{y} = -i\hbar\left(\cos\phi \frac{\partial}{\partial\theta} - \cot\theta\sin\phi \frac{\partial}{\partial\phi} \! \right) }

and

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \hat{L}_{z} = -i\hbar\frac{\partial}{\partial \phi}.}

Problem

(Richard L. Liboff, Introductory Quantum Mechanics, 2nd Edition, pp. 377-379)

Show, using the above results, that the operator,

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \hat{R}_{\Delta\phi}=\exp \left (\frac{i}{\hbar}\Delta\phi\hat{L}_z\right ),}

when applied to a function Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(\phi)\!} of the azimuthal angle Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi,\!} rotates the angle Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi\!} to Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi+\Delta\phi.} That is, show that

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \hat{R}_{\Delta\phi}f(\phi)=f(\phi+\Delta\phi).}

Solution