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| '''(1)''' A system is initally in the state, | | '''(1)''' A system is initally in the state, |
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| <math>\psi(\theta,\phi)=1/\sqrt{5}Y_1^{-1}(\theta,\phi)+\sqrt{3/5}Y_1^0(\theta,\phi)+1/\sqrt{5}Y_1^1(\theta,\phi).</math> | | <math>\psi(\theta,\phi)=\frac{1}{\sqrt{5}}Y_1^{-1}(\theta,\phi)+\sqrt{\frac{3}{5}}Y_1^0(\theta,\phi)+\frac{1}{\sqrt{5}}Y_1^1(\theta,\phi).</math> |
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| Find the possible results of a measurement of <math>\hat{L}_z</math> and the probabilities of finding each value. | | Find the possible results of a measurement of <math>\hat{L}_z</math> and the probabilities of finding each value. |
We will now find the orbital angular momentum eigenfunctions
in terms of position. Recall from the previous section that
If we act on the left with a position eigenvector
then this becomes
or, introducing
We may now separate out the
dependence from the
and
dependences; i.e.,
Solving for the
dependence, we obtain
We may now determine the
dependence by using the fact that
In the position basis, the raising and lowering operators are given by
We thus obtain
Solving the above equation, we find that the full wave function is
where
is an arbitrary function of
Note that this function may (and, as we will see in the next chapter, does) depend on
We may now find the wave functions
by repeated application of
It turns out to be
where
is an associated Legendre function. One may also write this as
where
are the spherical harmonics.
In the next chapter, we will be considering particles in central potentials, which are potentials that depend only on the distance
of the moving particle from a fixed point, usually the coordinate origin. Since the resulting forces produce no torque, the orbital angular momentum is conserved. In quantum mechanical terms, this means that the angular momentum operator commutes with the Hamiltonian. Therefore, the results developed throughout this chapter will be very useful in discussing such potentials.
Problems
(1) A system is initally in the state,
Find the possible results of a measurement of
and the probabilities of finding each value.
Solution
An exercise with angular momentum.