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| | ==WKB method for the Coulomb Potential == |
| | |
| | For the coulomb potential, the potential is given by: |
| | :<math> V(r) = -\frac{-Ze^2}{r} </math> |
| | |
| | Since the electron is bound to the nucleus, it can be veiwed as moving between two rigid walls at <math> r = 0 \!</math> and <math> r = a \!</math> with energy <math> E = V(a), a = -\frac{-Ze^2}{E}\!</math>. Thus, the energy of the electron is negative. |
| | |
| | The energies of the s-state (<math> \ell = 0 \!</math>) can be obtained from: |
| | |
| | :<math> \int_0^a \sqrt{2m\left(E+\frac{Ze^2}{r}\right)}dr = n\pi\hbar </math> |
| | |
| | Using the change of variable: <math> x = \frac{a}{r} </math> |
| | |
| | :<math> |
| | \begin{align} |
| | \int_0^a \sqrt{2m\left(E+\frac{Ze^2}{r}\right)}dr &= \sqrt{-2mE} \int_0^a dr \sqrt{\frac{a}{r} - 1} \\ |
| | &= a\sqrt{-2mE} \int_0^1 dx\sqrt{\frac{1}{x} - 1} \\ |
| | &= \frac{\pi}{2}a\sqrt{-2mE} \\ |
| | &= -Ze^2\pi\sqrt{-\frac{2m}{E}} |
| | \end{align} |
| | </math> |
| | |
| | Where I have used the integral |
| | :<math> \int_0^1\sqrt{\frac{1}{x} -1} = \frac{\pi}{2} </math> |
| | |
| | Thus we have the expression: |
| | :<math>-Ze^2\pi\sqrt{-\frac{2m}{E}} = n\pi\hbar </math> |
| | :<math>\Rightarrow E_n = -\frac{mZ^2e^4}{\hbar^2} = -\frac{Z^2e^2}{2a_0}</math> |
| | |
| | Where <math> a_0\!</math> is the Bohr radius. Notice that this is the correct expression for the energy levels of a Coulomb potential. |
| | |
| | [[Phy5645/Gamowfactor|Calculation of Gamow factor using WKB Aprroximation Method]] |
Revision as of 15:06, 14 August 2013
It is possible to apply the WKB approximation to the radial equation using a method by R. E. Langer (1937).
Recall:
,
Now apply the transformations:
Note that for
varying from 0 to infinity,
will vary from minus infinity to plus infinity.
The radial equation then transforms into:
In this case the Bohr-Sommerfeld quantization rule becomes:
?
For a central potential:


Worked Problem
Worked by team
WKB method for the Coulomb Potential
For the coulomb potential, the potential is given by:

Since the electron is bound to the nucleus, it can be veiwed as moving between two rigid walls at
and
with energy
. Thus, the energy of the electron is negative.
The energies of the s-state (
) can be obtained from:

Using the change of variable:

Where I have used the integral

Thus we have the expression:


Where
is the Bohr radius. Notice that this is the correct expression for the energy levels of a Coulomb potential.
Calculation of Gamow factor using WKB Aprroximation Method