We now solve the isotropic harmonic oscillator using the formalism that we have just developed. While it is possible to solve it in Cartesian coordinates, we gain additional insight by solving it in spherical coordinates, and it is easier to determine the degeneracy of each energy level.
The radial part of the Schrödinger equation for a particle of mass
in an isotropic harmonic oscillator potential
is given by:

We look at the solutions
in the asymptotic limits of
.
As
, the equation reduces to

whose nondivergent solution is given by
.
On the otherhand, as
, the equation becomes

whose solution is given by
.
Combining the asymptotic limit solutions we choose the general solution to the equation as

Substituting this expression into the original equation,
![{\displaystyle {\frac {\partial ^{2}f_{l}(r)}{\partial r^{2}}}+2\left({\frac {l+1}{r}}-{\frac {Mw}{\hbar }}r\right){\frac {\partial f_{l}(r)}{\partial r}}+\left[{\frac {2ME}{\hbar ^{2}}}-(2l+3){\frac {Mw}{\hbar }}\right]f_{l}(r)=0}](https://wikimedia.org/api/rest_v1/media/math/render/svg/e9af28f69669ff04ae10eb8cafb49b31b3f5531e)
Now we try the power series solution

Substituting this solution into the reduced form of the equation,
![{\displaystyle \sum _{n=0}^{\infty }\left[n(n-1)a_{n}r^{n-2}+2\left({\frac {l+1}{r}}-{\frac {Mw}{\hbar }}\right)na_{n}r^{n-1}+\left[{\frac {2ME}{\hbar ^{2}}}-(2l+3){\frac {Mw}{\hbar }}\right]a_{n}r^{n}\right]=0}](https://wikimedia.org/api/rest_v1/media/math/render/svg/24873401d1209b1aeaf8f4d2c1fec73b8621a98d)
which reduces to the equation
![{\displaystyle \sum _{n=0}^{\infty }\left[n(n+2l+1)a_{n}r^{n-2}+\left(-{\frac {2Mw}{\hbar }}n+{\frac {2ME}{\hbar ^{2}}}-(2l+3){\frac {Mw}{\hbar }}\right)a_{n}r^{n}\right]=0}](https://wikimedia.org/api/rest_v1/media/math/render/svg/c8d9a61f2e496e08807dace77831fd98ab01783a)
For this equation to hold, the coefficients of each of the powers of r must vanish seperately.
So,when
the coefficient of
is zero,
implying that
need not be zero.
Equating the coefficient of
to be zero,
implying that
must be zero.
Equating the coefficient of
to be zero, we get the recursion relation which is:
![{\displaystyle \sum _{n=0}^{\infty }(n+2)(n+2l+3)a_{n+2}=\left[-{\frac {2ME}{\hbar ^{2}}}+(2n+2l+3){\frac {Mw}{\hbar }}\right]a_{n}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/120c9f46e40979f46f2ab40ce065219547dc9a66)
The function
contains only even powers in n and is given by:

Now as
,
diverges so that for finite solution, the series should stop after
leading to the quantization condition:


As a result, the energy of the isotropic harmonic oscillator is given by:
with 
The degeneracy corresponding to the nth level is:

The total wavefunction of the isotropic Harmonic Oscillator is given by:
