Worked Problem about angular momentum.
We will now find the orbital angular momentum eigenfunctions
in terms of position. Recall from the previous section that
If we act on the left with a position eigenvector
then this becomes
or, introducing
We may now separate out the Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi}
dependence from the
and
dependences; i.e.,
Solving for the
dependence, we obtain
We may now determine the
dependence by using the fact that
Writing this in the position basis as before, we obtain

Where the eigenvalues of
are:

We proceed by using the property of
and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle L_-\!}
, defined by

to find the following equation

Using the above equations, we get

And the solution is

where
is an arbitrary function of
. We can find the angular part of the solution by using
. It turns out to be

And we know that
are the spherical harmonics defined by

where the function with cosine argument is the associated Legendre polynomials defined by:

with

And so we then can write:

Central forces are derived from a potential that depends only on the distance r of the moving particle from a fixed point, usually the coordinate origin. Since such forces produce no torque, the orbital angular momentum is conserved.
We can rewrite the angular momentum as

As has been shown, angular momentum acts as the generator of rotation.
An exercise with angular momentum.