Stationary states are the energy eigenstates of the Hamiltonian operator. These states are called "stationary" because their probability distributions are independent of time.
For a conservative system with a time independent potential,
, the Schrödinger equation takes the form:
![{\displaystyle i\hbar {\frac {\partial \Psi ({\textbf {r}},t)}{\partial t}}=\left[-{\frac {\hbar ^{2}}{2m}}\nabla ^{2}+V({\textbf {r}})\right]\Psi ({\textbf {r}},t)}](https://wikimedia.org/api/rest_v1/media/math/render/svg/9ff4d2352b860ab251182602acebf87543b3b5a5)
Since the potential and the Hamiltonian do not depend on time, solutions to this equation can be written as
.
Obviously, for such state the probability density is

which is independent of time. Hence, the name is "stationary state".
The same thing happens in calculating the expectation value of any dynamical variable.
For some operator

The Schrödinger equation now becomes
![{\displaystyle \left[-{\frac {\hbar ^{2}}{2m}}\nabla ^{2}+V({\textbf {r}})\right]\psi ({\textbf {r}})=E\psi ({\textbf {r}})}](https://wikimedia.org/api/rest_v1/media/math/render/svg/4e80d2d34fde6c1fa4546dae66011fff67105b81)
which is an eigenvalue equation with eigenfunction
and eigenvalue
. This equation is known as the time-independent Schrödinger equation.
Problem
The time-independent Schrodinger equation for a free particle is given by

Typically, one lets
to simplify the equation

Show that (a) a plane wave
, and (b) a spherical wave
where
, satisfy the equation. (In either case, the wave length of the solution is given by
and the momentum by de Broglie's relation
. )
A sample problem: Free Particle SE Problem.